Short answer: Yes.
Longer: Perl 6 allows you to over-ride the names of routines. 's' is a
routine. You over-rode it.
Perl 6 is different from most other languages because it uses multiple
dispatch. Effectively this means it is not just the name of the
subroutine (s) that matters, but also it
The following code:
use v6;
my $str = 'abc';
sub s {1};
say s;
$str ~~ s:g/ b /x/;
dd $str;
say $/;
outputs:
1
Str $str = "axc"
(｢b｣)
as expected.
But, just remove the :g global flag and:
===SORRY!=== Error while compiling /home/hogaboom/hogaboom/Perl6/p6ex/./t.p6
Undeclared routine:
On Fri, 14 Sep 2018 18:15:21 -0400
Brandon Allbery wrote:
> Magic variables make multiple threads impossible, which is why perl 5
> is stuck with ithreads: what happens if two threads each "run"
> something at around the same time?
>
> In Perl 6, you have a Proc object for each subprocess, and c
And that is the way to test it.
but then I cant work out how to get the message. I've been looking at
Zoffix's Test::Output, but not
Incomplete sentence there. I guess it doesn't work for you? Tell
us how you tried to use it, what you were expecting, and what happened
instead.
On Sun, Oct 21, 2018, 12:09 Richard Hainsworth
wrote:
> I am trying to find a way to send a message via STDERR to a user, and to
> exit, but to eliminate the backtrace printing.
>
> so .. either I use your suggestion of 'exit note $message' which I find
> elegant, but so far difficult to test.
>
