On 07/29/2018 03:03 AM, Patrick Spek via perl6-users wrote:
You can use the head[2] sub to write it as
for @ReturnAry.head(*.elems - 3) -> $line
Also, on the
$ReturnStr += $Line
If you're trying to concatenate a string, you should use the ~ instead
of the +, so it'd become
$Re
*From:* Brandon Allbery
*Sent:* Saturday, July 28, 2018 16:22
*To:* ToddAndMargo
*Cc:* perl6-users
*Subject:* Re: return code?
Yes, that's what I was addressing: you can tell run() to do that,
keeping stderr separate with :err(). qxx does that internally.
On Sat, Jul 28, 2018 at 4:12 PM Tod
Hi,
Try this:
my $stringy = "abc";
say $stringy.^parents(:all);
This should display:
((Cool) (Any) (Mu))
Cheers,
Laurent.
2018-07-29 19:27 GMT+02:00 Joseph Brenner :
> If you look at the type diagram:
>
> https://docs.perl6.org/type/Str#___top
>
> You can see that:
>Str is Cool is An
I think you want ^mro?
On Sun, Jul 29, 2018 at 1:28 PM Joseph Brenner wrote:
> If you look at the type diagram:
>
> https://docs.perl6.org/type/Str#___top
>
> You can see that:
>Str is Cool is Any is Mu
>
> But if you use the ^parents method on a string, you don't get
> "Cool", instead you
If you look at the type diagram:
https://docs.perl6.org/type/Str#___top
You can see that:
Str is Cool is Any is Mu
But if you use the ^parents method on a string, you don't get
"Cool", instead you get "()":
my $stringy = "abc";
say $stringy.^name; # Str
say $stringy.^parents;
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA256
I'd gladly help you get your first module published.
First off, you'll need to have a META6.json describing which files your
module will provide, and which dependencies it needs. You always will
need this json file, even if you have no dependencies.
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA256
I get the idea that you're trying to get a list of lines with the
@ReturnAry = split "\n", qqx ( curl $TimeOutStr -L $Url -o
$FileName; echo \$\? );
You can use the lines[1] sub for exactly this. Similarly for this line
for @ReturnAry[
On 07/28/2018 11:46 PM, ToddAndMargo wrote:
On 07/28/2018 01:37 AM, ToddAndMargo wrote:
Hi All,
How do I get the bash return code ("$?") from
the following?
$ReturnStr = qqx ( curl $TimeOutStr -L $Url -o $FileName ).lines;
Many thanks,
-T
Followup:
This is what I came up with:
if $P
