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Daniel Ruoso wrote:
> Jon Lang wrote:
>> The key to understanding roles is to note that roles don't implement
>> methods; classes implement methods.
>
> Er, while I see your point, Roles are not just interfaces... they are OO
> components that can be plugged into other classes. They often are used
On Jul 12, 2009, at 20:15 , David Green wrote:
sub nighttime (Canine $rover) { $rover.bark if any(burglars()); }
(...)
3) $rover acts like a Canine, but the rest of the original $dogwood
arg (the Tree parts) are still there; they just aren't used unless
somehow explicitly brought out; for
On 2009-Jul-12, at 12:43 pm, Daniel Ruoso wrote:
role R1 {
method foo() {...} # degenerates to interface
}
Just wondering: since merely declaring an interface will be common
enough, should we be able to say simply "method foo;" inside a role,
and drop the {...}?
class Bla does R2 {
m
On 2009-Jul-10, at 4:37 pm, Jon Lang wrote:
This is one of the distinctions between role composition and class
inheritance. With class inheritance, the full tree of inherited
classes is publicly accessible; with role composition, the methods
of the combined role are the only ones that are m
# New Ticket Created by Moritz Lenz
# Please include the string: [perl #67480]
# in the subject line of all future correspondence about this issue.
# http://rt.perl.org/rt3/Ticket/Display.html?id=67480 >
Rakudo: 08928df70e4af4013eb0bfde02256262728ecf6e
$ perl6 -e 'my @a = ; say @a...@a()'
Ca
Minimiscience wrote:
> I tried to find the answers to these in the Synopses, but I couldn't.
> Plan B is to ask the mailing list.
>
> - What does the "first" method/subroutine return when no elements of
> the list match? Does it return the empty list? Does the return value
> count as un
Em Dom, 2009-07-12 às 22:51 +0200, Moritz Lenz escreveu:
> I setting of OUTER::$/ considered syntactic sugar?
> I don't care either way, I'd just like some clarification so that I can
> write tests and submit tickets (if appropriate).
As far as I remember, it's not really OUTER::$/, but each routi
payload++ brought this up on #perl6:
in current Rakudo, $string ~~ /re/ sets $/ in the scope in which the
expression appears, ie
'a' ~~ /./;
say $/; # ouput: a
But $str.match(..) and $str.subst don't. The spec is rather silent, it
says "There are also method forms of m// and s///: [...]
Em Sex, 2009-07-10 às 15:39 -0700, Jon Lang escreveu:
> The key to understanding roles is to note that roles don't implement
> methods; classes implement methods.
Er, while I see your point, Roles are not just interfaces... they are OO
components that can be plugged into other classes. They often
On Sun, Jul 12, 2009 at 9:29 AM, Minimiscience wrote:
> On Jul 12, 2009, at 12:07 AM, Chas. Owens wrote:
>>
>> Since grep is defined as returning a list of matching elements and first
>> is
>> defined as being the same as grep, I would say that it returns an empty
>> list
>> if nothing matches. Th
On Jul 12, 2009, at 9:46 AM, Patrick R. Michaud wrote:
".?method" seems to work for me in Rakudo:
$ cat x
my $x = undef;
say ($x.?foo).perl;
$ ./perl6 x
undef
This doesn't work when the variable is assigned to a typed container:
#!/usr/bin/env perl6
use v6;
my Str
On Jul 12, 2009, at 12:07 AM, Chas. Owens wrote:
Since grep is defined as returning a list of matching elements and
first is
defined as being the same as grep, I would say that it returns an
empty list
if nothing matches. The empty list is one of the false values.
Does the empty list count
On Sun, Jul 12, 2009 at 12:07:14AM -0400, Chas. Owens wrote:
> On Sat, Jul 11, 2009 at 22:02, Minimiscience wrote:
> > - How does one declare multiple variables of the same type with a single
> > "my" statement? Is it "my Int ($x, $y);", "my(Int $x, Int $y);", or
> > something else? Are the pare
# New Ticket Created by Minimiscience
# Please include the string: [perl #67466]
# in the subject line of all future correspondence about this issue.
# http://rt.perl.org/rt3/Ticket/Display.html?id=67466 >
- Time::gmtime doesn't handle having an optional argument well:
$ perl6
> sa
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