I try to create a table called group. I get an error saying:
'You have an error in your SQL syntax near 'Group (Group_ID
TINYINT(3) NOT NULL AUTO_INCREMENT PRIMARY KEY)' at line 1.
What's wrong with this?
TIA
--
David S. Jackson
ID order by
i.Category_ID;
My intention was to have the Number field simple be a number that
increments by one for each line that prints out. But, of course,
the documentation says that's not what the "count" function is
for.
How can I add a simple little old line count
his is from the /var/log/apache/error.log file.
Any ideas what might be going wrong?
TIA.
--
David S. Jackson[EMAIL PROTECTED]
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Nirvana? That's the place where the powers that be
and their friends hang ou
en when I select * in Contributors where Name = "Somebody
Lastname"; The values haven't been updated. They remain 0
and 0.
What gives? Is this a foreign key problem?
TIA.
PS. Oh yeah, I'm using mysql 3.22 on debian 2.2.
guous
So, looking again at my definitions for Contributor_ID in both
tables, I see they aren't exactly alike. Is there a way I can
make Contributor_ID in Item refer back to the Index
(Contributor_ID) in Contributors? I gather that just making the
data types the same is not enough
d.
Is there any easy way to recover that information? Is there an
undo command?
--
David S. Jackson[EMAIL PROTECTED]
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
You can't have everything. Where would you
Hi,
I'm just starting my first MySQL db, and I'm going to want to
print out reports from it and produce a camera-ready document.
Has anyone done this before, using, say, Star Office or AbiWord
or something?
TIA.
--
David S. Jackson[EMAIL
ibutors' table
handle more than Contact_ID and more than one Volunteer_ID.
Don't I want each Contact_ID field for each record to be a single
discrete ID number? How would you guys handle this?
TIA!
--
David S. Jackson[EMAIL PROTECTED]
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
