RE: Within-group aggregate query help please - customers and latest subscription row

2011-10-25 Thread Hal�sz S�ndor
2011/10/24 16:31 -0700, Daevid Vincent WHERE cs.customer_id = 7 GROUP BY customer_id Well, the latter line is now redundant. How will you make the '7' into a parameter? -- MySQL General Mailing List For list archives: http://l

RE: Within-group aggregate query help please - customers and latest subscription row

2011-10-24 Thread Daevid Vincent
October 24, 2011 4:06 PM > To: mysql@lists.mysql.com > Subject: RE: Within-group aggregate query help please - customers and latest > subscription row > > A kind (and shy) soul replied to me off list and suggested this solution, > however, > this takes 28 seconds (that's f

RE: Within-group aggregate query help please - customers and latest subscription row

2011-10-24 Thread Daevid Vincent
- > From: Daevid Vincent [mailto:dae...@daevid.com] > Sent: Monday, October 24, 2011 1:46 PM > To: mysql@lists.mysql.com > Subject: Within-group aggregate query help please - customers and latest > subscription row > > I know this is a common problem, and I've been struggling

Within-group aggregate query help please - customers and latest subscription row

2011-10-24 Thread Daevid Vincent
I know this is a common problem, and I've been struggling with it for a full day now but I can't get it. I also tried a few sites for examples: http://www.artfulsoftware.com/infotree/queries.php#101 http://forums.devarticles.com/general-sql-development-47/select-max-datetime -problem-10210.html