Hi!!
$dbQuery = "select * from table where 1" ;
$result = mysql_query($dbQuery) or die("Error trying to execute the query:
".mysql_error());
If(mysql_num_rows($result)<1){ //also: "==0" works
echo "NULL";
-Original Message-
From: Kane Wilson [mailto:[EMAIL PROTECTED]
Sent: Wednes
Hello.
> $dbQuery = results;
Have you forgotten to put '$' before the 'results'? Do you
have display_errors = On in your php.ini?
Kane Wilson <[EMAIL PROTECTED]> wrote:
>
>
> hi ,
>
> I wanted to check the following condition and if it is
> success i wanted to display a massag
Kane Wilson wrote:
I wanted to check the following condition and if it is
success i wanted to display a massage.I tried as
follows. but no luck. nothing displayed.
$dbQuery = results;
$result = mysql_query($dbQuery) or die("Couldn't get
file list");
if (!isset($result))
{echo "NULL";}