Lee
>I think the formula is just right - very clever. But is it
possible to make
>sure that col1, col2 and col3 are all from the same record?
Different question, different answer I ween
:-)
SET @n = ;
SELECT
id,
MIN( LEAST( ABS(@n-col1), LEAST( ABS(@n-col2), ABS(@n-cl3) ))) AS min
F
Peter Brawley wrote:
/>Is there an efficient way to find the closest numerical value, across
>three columns? I do not know if there is a way to find it across one. /
Not sure about efficiency, but if the criterion number is @n, do you
mean ...
SELECT LEAST( ABS(MIN(@n-col1)),
LE
>Is there an efficient way to find the closest numerical value,
across
>three columns? I do not know if there is a way to find it across
one.
Not sure about efficiency, but if the criterion number is @n, do you
mean ...
SELECT LEAST( ABS(MIN(@n-col1)),
LEAST( ABS(MIN(@n-col2))
