Re: Multi table update

2004-12-30 Thread Kai Ruhnau
he client can get / must be aware of. - The equivalence between severel joins remains. Greetings Kai -- Kai Ruhnau Software t a r g e t systemelectronic gmbh kölner str. 99 42651 Solingen germany Tel: +49 (0)212 22 20 9 - 710 Fax: +49 (0)212 20 10 45 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]

Re: Multi table update

2004-12-30 Thread Kai Ruhnau
won't be. [snip] Just in case, I filled bug report number #7590. Feel free to add your comment. Greetings Kai -- Kai Ruhnau Software t a r g e t systemelectronic gmbh kölner str. 99 42651 Solingen germany Tel: +49 (0)212 22 20 9 - 710 Fax: +49 (0)212 20 10 45 -- MySQL General Mailing Lis

RE: Multi table update

2004-12-29 Thread Kai Ruhnau
Zitat von Jay Blanchard <[EMAIL PROTECTED]>: > [snip] > Although my question goes in that direction, it is more about why this > statement > does not act atomically from my applications point of view. > > > update table2, table1 > > SET table2.value=table2.value-IF(table1.condition=7,1,0), > > tab

Re: Multi table update

2004-12-28 Thread Kai Ruhnau
Zitat von Jay Blanchard > [snip] > And the query: > > UPDATE table1 > INNER JOIN table2 ON table2.ID_table1=table1.ID > SET table2.value=table2.value-IF(table1.condition=7,1,0), > table1.condition=8 > WHERE table1.ID IN (1,2) > > After that the value's in table2 are still 5 and 2. But I would

Re: Multi table update

2004-12-28 Thread Kai Ruhnau
Zitat von [EMAIL PROTECTED]: > Can you provide us a test case (sample table definitions and sample data) > ? Sure. -- CREATE TABLE table1 ( ID int(10) unsigned NOT NULL default '0', condition int(10) unsigned NOT NULL default '0' ) TYPE=InnoDB; INSERT INTO table1 VALUES (1,7); INSERT INTO

Re: Multi table update

2004-12-28 Thread Kai Ruhnau
Zitat von [EMAIL PROTECTED]: > One reason may be due to your ON condition. > > ON table2.ID=table2.ID_table1 > > You reference table 2 twice and I doubt that on the table2 table id equals > id_table1 very often. Because table2 is LEFT JOINed to table1, you will > only be able to update the rows th

Multi table update

2004-12-28 Thread Kai Ruhnau
Sorry for duplicating this message. But I sent the other one with the wrong subject. Hi, An SQL-statement that is conceptually equal to the following caused some astonishment. UPDATE table1 LEFT JOIN table2 ON table2.ID=table2.ID_table1 SET table2.value=table2.value-IF(table1.condition=7,1,0),

Re: importing data

2004-12-28 Thread Kai Ruhnau
Hi, An SQL-statement that is conceptually equal to the following caused some astonishment. UPDATE table1 LEFT JOIN table2 ON table2.ID=table2.ID_table1 SET table2.value=table2.value-IF(table1.condition=7,1,0), table1.condition=8 WHERE table1.ID=$id My problem is the IF condition, which alway e

Row level locking with InnoDB

2004-08-24 Thread Kai Ruhnau
COUNT(ID). No rows, because no row is actually returned / selected. Thanks and greetings, Kai Ruhnau -- This signature is left as an exercise for the reader. -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]