Thanks Bryan. Your explanation makes things a lot clearer to me.
As mentioned in my reply to Daniel, I not cannot figure out why "$1f" will
be "".
On Fri, Sep 23, 2011 at 12:05 PM, Brynet wrote:
> One of the first things an MBR does is do a long jump from where the BIOS
> loaded it.
>
> The
On Fri, Sep 23, 2011 at 11:24 AM, Daniel Dickman wrote:
>
> What are you trying to do though? Working with x86 in real mode and dealing
> with ancient PC conventions is probably not the easiest place to start.
I'm trying to learn how kernel (or OS) works.
I went through a couple of books on OS de
One of the first things an MBR does is do a long jump from where the BIOS
loaded it.
The thing is, often you can't trust the BIOS to do the right thing, the x86 in
16-bit real mode uses segmented memory, so you may be at :07C0 or 7C00:
depending on the implementation. If you read the co
The 1: is the target for the preceding ljmp instruction. This is a local
label. Reference here:
http://sourceware.org/binutils/docs/as/Symbol-Names.html#Symbol-Names
The reason the ljmp is needed in the first place is because In real mode there
are multiple ways to refer to the same memory address
Hello,
Not sure if this is the right place to request help for this, but I'm
reading mbr.S file (i386 arch), but could not figure out what the function
is for the line that reads "1:".
The code below that line is setting up statck, but why do we need this line?
and there are more than one line tha
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