info request

2021-09-04 Thread Lourens
faq misc info misc intro misc **

Re: vi: count occurrences of a substring

2021-09-04 Thread Reuben ua Bríġ
> Date: Sun, 5 Sep 2021 09:11:21 +1000 > From: Reuben ua Bríġ > easy peasy. to sed all spaces into newlines you might as well just sed 'y/ /\n/' the inverse is almost as easy sed '1h;1!H;$!d;g;y/\n/ /' im sure yoar kicking yourself for not seeing such a simple solution.

Re: vi: count occurrences of a substring

2021-09-04 Thread Reuben ua Bríġ
> Date: Sun, 5 Sep 2021 09:11:21 +1000 > From: Reuben ua Bríġ > > Date: Sat, 4 Sep 2021 23:22:29 +0100 > > From: ropers > > > It's still a little disconcerting to me how getting sed to play nice > > with \n *from inside vi* still seems like a bridge too far > > easy peasy. to sed all spa

Re: vi: count occurrences of a substring

2021-09-04 Thread Reuben ua Bríġ
> Date: Sat, 4 Sep 2021 23:22:29 +0100 > From: ropers > It's still a little disconcerting to me how getting sed to play nice > with \n *from inside vi* still seems like a bridge too far easy peasy. to sed all spaces into newlines from nvi, enter :!sed 's/ /&^V^M/g;y/^V^M/\n/' echoed a

Re: vi: count occurrences of a substring

2021-09-04 Thread ropers
On 04/09/2021, Parodper wrote: > O 04/09/21 ás 18:25, ropers escribiu: >> On 04/09/2021, Parodper wrote: >>> So I wrote >>> :!sed s/abc/abc\/g % | grep -c abc >>> and then went back and pressed after that backslash, i.e. >>> :!sed s/abc/abc\/g % | grep -c abc >>> And it gave me a correct number

vi: count occurrences of a substring

2021-09-04 Thread ropers
On 04/09/2021, Marc Chantreux wrote: > hello, > >> :!sed s/abc/abc\n/g % | grep -c abc > > Note: in sed, "what i just matched" is noted & Oh, that's good, thank you. *Shoulda seenit on the man page -- butta dinnt.* >From sed(1): > An ampersand (‘&’) appearing in the replacement is replaced

Re: vi: count occurrences of a substring

2021-09-04 Thread Kastus Shchuka
On Sat, Sep 04, 2021 at 05:00:29PM +0100, ropers wrote: > However, that's as inaccurate as, or potentially even more inaccurate > than your version, at least as far as vim-ilarity is concerned. My > awk-ward incantation matches vim's :%s/abc//gn precisely. Not sure if this is less "awk-ward": :%

Re: vi: count occurrences of a substring

2021-09-04 Thread Parodper
O 04/09/21 ás 18:25, ropers escribiu: On 04/09/2021, Parodper wrote: So I wrote :!sed s/abc/abc\/g % | grep -c abc and then went back and pressed after that backslash, i.e. :!sed s/abc/abc\/g % | grep -c abc And it gave me a correct number of abc's for my test text. I feel like the dumbest p

Re: vi: count occurrences of a substring

2021-09-04 Thread Marc Chantreux
> Otherwise, if I try to just type > :!sed s/abc/abc\/g % | grep -c abc > and press enter, I only get the same output I also get out of same here! I so much wish it worked! regards marc

(technology sucks anyway) Re: vi: count occurrences of a word

2021-09-04 Thread Marc Chantreux
hello, > That's a neat trick -- IFF you can be *sure* that character won't show > up in the text. I also feel it's a workaround this is ok as you can easily check if if the caracter won't show. this is a "good enough" principle: don't try to fix *all* the cases, just fix yours. > understand *why

Re: vi: count occurrences of a word

2021-09-04 Thread Marc Chantreux
hello, > :!sed s/abc/abc\n/g % | grep -c abc Note: in sed, "what i just matched" is noted & > Googled information suggests that the opposite of what's described in > the man page may be true: You CAN use a literal newline, but you > can't use \n. BSD sed is more litteral AFAIK so you need to

vi: count occurrences of a substring

2021-09-04 Thread ropers
On 04/09/2021, Parodper wrote: > I think I found something. From POSIX > (https://pubs.opengroup.org/onlinepubs/9699919799/utilities/sed.html): > > A line can be split by substituting a into it. The > > application shall escape the in the replacement by preceding > > it by a . Are you or is

Re: vi: count occurrences of a substring

2021-09-04 Thread ropers
On 04/09/2021, Marc Chantreux wrote: > > :w !tr -cs '[:alnum:]' '\n'|grep -c abc > Is tr's -s option there to eliminate multiple newlines? If so, is there harm in omitting it, since grep won't count those anyway? :w !tr -c '[:alnum:]' '\n' | grep -c abc I think your one-liner is not bad.

Re: vi: count occurrences of a word

2021-09-04 Thread Parodper
O 04/09/21 ás 14:26, ropers escribiu: On 04/09/2021, Parodper wrote: To use newlines with sed I use tr and a char I know does not appear on the text, like '|' or '`'. I just tested :!sed s/abc/abc€/g % | tr '€' '\n' | grep -c abc and it worked fine. That's a neat trick -- IFF you can be *sure

Re: vi: count occurrences of a word

2021-09-04 Thread ropers
On 04/09/2021, Parodper wrote: > To use newlines with sed I use tr and a char I know does not appear on > the text, like '|' or '`'. I just tested > :!sed s/abc/abc€/g % | tr '€' '\n' | grep -c abc > and it worked fine. That's a neat trick -- IFF you can be *sure* that character won't show up in

Re: vi: count occurrences of a word

2021-09-04 Thread Marc Chantreux
hello, > > so you can write: > > > > :w|grep -c abc % > That doesn't really fit the bill: > 1. This error message is produced: 'The grep command is unknown' because i wasted it by missing the bang :w|!grep -c abc % is a single line way to write :w :!grep -c abc % > 2. grep

Re: vi: count occurrences of a word

2021-09-04 Thread Parodper
O 04/09/21 ás 12:12, ropers escribiu: However, I can't get the newline to work right in OpenBSD's sed. It does work in GNU sed. man sed has this: The escape sequence \n matches a newline character embedded in the pattern space. You can't, however, use a literal newline character in an addres

Re: vi: count occurrences of a word

2021-09-04 Thread ropers
Self-follow-up: I. I've just realised I made a careless error in trying to literally reproduce your careless mistake, even though it should have been obvious this was incorrect or at least incomplete. Instead of just :w !grep -c clearly you meant: :w !grep -c abc Though as noted before,