That doesn't seem to be right, you had a typename before:
(lldb) pp Ty
Fn(Void -> Int)*
=
Make sure everything is setup and is where you were stopped before and that you
use the same "Ty" variable you did before. I have seen function types have
newlines in them in the past.
> On Aug 24, 2015,
Hm, that doesn't seem to be it.
(lldb) pp R
var ~UnType
typename = ""
() =
On Mon, Aug 24, 2015 at 12:51 PM, Greg Clayton wrote:
> The type name for "Ty" might have a newline in it. Try this:
>
>
>res = frame.EvaluateExpression("%s->dump()" % command)
>print >>result, 'typename = "%s"'
The type name for "Ty" might have a newline in it. Try this:
res = frame.EvaluateExpression("%s->dump()" % command)
print >>result, 'typename = "%s"' % (res.GetType().GetName())
print >>result, res
See if the double quote is on the next line.
> On Aug 22, 2015, at 11:58 AM, Ramkumar Ra
Hi,
My script is simple enough:
import lldb
def pp(debugger, command, result, internal_dict):
target = debugger.GetSelectedTarget()
process = target.GetProcess()
thread = process.GetSelectedThread()
frame = thread.GetSelectedFrame()
res = frame.EvaluateExpression("%s->dump()"
