Re: [PATCH 08/21] memblock: drop __memblock_alloc_base()

2019-01-16 Thread Rob Herring
On Wed, Jan 16, 2019 at 7:45 AM Mike Rapoport wrote: > > The __memblock_alloc_base() function tries to allocate a memory up to the > limit specified by its max_addr parameter. Depending on the value of this > parameter, the __memblock_alloc_base() can is replaced with the appropriate > memblock_ph

[PATCH 08/21] memblock: drop __memblock_alloc_base()

2019-01-16 Thread Mike Rapoport
The __memblock_alloc_base() function tries to allocate a memory up to the limit specified by its max_addr parameter. Depending on the value of this parameter, the __memblock_alloc_base() can is replaced with the appropriate memblock_phys_alloc*() variant. Signed-off-by: Mike Rapoport --- arch/sh