From: James Bottomley
> Sent: 25 October 2018 16:33
>
> On Thu, 2018-10-25 at 16:13 +0100, Colin King wrote:
> > From: Colin Ian King
> >
> > In the expression "ahc_inb(ahc, port+3) << 24", the initial value is
> > a u8, but is promoted to a signed int, then sign-extended to
> > uint64_t.
>
> Wh
On Thu, 2018-10-25 at 16:13 +0100, Colin King wrote:
> From: Colin Ian King
>
> In the expression "ahc_inb(ahc, port+3) << 24", the initial value is
> a u8, but is promoted to a signed int, then sign-extended to
> uint64_t.
Why is this, that's highly non intuitive? The compiler is supposed to
p
On Thu, 2018-10-25 at 16:13 +0100, Colin King wrote:
> From: Colin Ian King
>
> In the expression "ahc_inb(ahc, port+3) << 24", the initial value is a
> u8, but is promoted to a signed int, then sign-extended to uint64_t. If
> the value read from the port has the upper bit set then the sign
> ex
From: Colin Ian King
In the expression "ahc_inb(ahc, port+3) << 24", the initial value is a
u8, but is promoted to a signed int, then sign-extended to uint64_t. If
the value read from the port has the upper bit set then the sign
extension will set all the upper bits of the expression which is pr
4 matches
Mail list logo
