Sridhar Samudrala a écrit :
> I think the following patch
>
> [IPV6] MCAST: Fix joining all-node multicast group on device initialization.
> http://www.spinics.net/lists/netdev/msg22663.html
>
> that went in after 2.6.20-rc5 should fix this problem.
>
Yep that fixes the problem. Thanks a lot.
On Wed, Jan 17, 2007 at 12:30:53AM +0100, bert hubert wrote:
> On Tue, Jan 16, 2007 at 10:42:53PM +0100, Aurelien Jarno wrote:
>
> > I have just tried a 2.6.20-rc5 kernel (I previously used a 2.6.19 one),
> > and I have noticed that the IPv6 router advertisement functionality is
>
> Can you check
Aurelien Jarno wrote:
Hi all,
I have just tried a 2.6.20-rc5 kernel (I previously used a 2.6.19 one),
and I have noticed that the IPv6 router advertisement functionality is
broken. The interface is not attributed an IPv6 address anymore, despite
/proc/sys/net/ipv6/conf/all/ra_accept being set to
I think the following patch
[IPV6] MCAST: Fix joining all-node multicast group on device initialization.
http://www.spinics.net/lists/netdev/msg22663.html
that went in after 2.6.20-rc5 should fix this problem.
Thanks
Sridhar
On 1/16/07, bert hubert <[EMAIL PROTECTED]> wrote:
On Tue, Jan 16,
On Tue, Jan 16, 2007 at 10:42:53PM +0100, Aurelien Jarno wrote:
> I have just tried a 2.6.20-rc5 kernel (I previously used a 2.6.19 one),
> and I have noticed that the IPv6 router advertisement functionality is
Can you check if rc1, rc2, rc3 etc do work?
Thanks.
--
http://www.PowerDNS.com
Aurelien Jarno wrote:
> I have just tried a 2.6.20-rc5 kernel (I previously used a 2.6.19 one),
> and I have noticed that the IPv6 router advertisement functionality is
> broken. The interface is not attributed an IPv6 address anymore, despite
> /proc/sys/net/ipv6/conf/all/ra_accept being set to 1
Hi all,
I have just tried a 2.6.20-rc5 kernel (I previously used a 2.6.19 one),
and I have noticed that the IPv6 router advertisement functionality is
broken. The interface is not attributed an IPv6 address anymore, despite
/proc/sys/net/ipv6/conf/all/ra_accept being set to 1 (also true for each
i
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