Re: beam subdivision problem

2024-07-08 Thread Werner LEMBERG
>> The Alain and Rachmaninov only have one fewer beam, so the beam >> count between the groups is not appropriate for the lengths of the >> subdivided groups, according to the Gould rules.  Personally, I >> think the Gould rules are correct, but two of the music publishers >> in your example do no

Re: beam subdivision problem

2024-07-07 Thread Simon Albrecht
On 04.07.24 19:00, Carl Sorensen wrote: The Alain and Rachmaninov only have one fewer beam, so the beam count between the groups is not appropriate for the lengths of the subdivided groups, according to the Gould rules.  Personally, I think the Gould rules are correct, but two of the music publ

Re: beam subdivision problem

2024-07-04 Thread Jason Yip
On 2024-07-04 09:09, Jason Yip - sripedia_getpgrp(a)slmail.me wrote: On 2024-07-03 22:06, Werner LEMBERG - wl(a)gnu.org wrote: Even though you want this special subdivision at just one point in your example, do you have examples where this special subdivision occurs at multiple points in the sam

Re: beam subdivision problem

2024-07-04 Thread Carl Sorensen
On Wed, Jul 3, 2024 at 11:07 PM Werner LEMBERG wrote: > > OK, here are some scans that I've found. As you can see, this kind of > subdivision is not so special as previously assumed. > > * Jehan Alain, trois danses – Deuils (for organ), (publisher: Leduc) > > * Prokofiev, piano sonata 7, op. 83,

Re: beam subdivision problem

2024-07-04 Thread Jason Yip
On 2024-07-03 22:06, Werner LEMBERG - wl(a)gnu.org wrote: Even though you want this special subdivision at just one point in your example, do you have examples where this special subdivision occurs at multiple points in the same beam? My former suggestion acts as a offset of # of beamlets for eve

Re: beam subdivision problem

2024-07-03 Thread Werner LEMBERG
> I have thought of a probably better solution. Currently, if > `minimumBeamSubdivisionInterval` > `maximumBeamSubdivisionInterval`, > the algorithm basically pretends that `subdivideBeams` is false. > What if I change the behavior of that case such that you can add > `maximumBeamSubdivisionInterv

Re: beam subdivision problem

2024-07-03 Thread Werner LEMBERG
> This may be slightly less ugly, but it still requires a function > call every place you want a beam subdivision: Thanks! Werner

Re: beam subdivision problem

2024-07-03 Thread Jason Yip
On 2024-07-02 21:33, Werner LEMBERG - wl(a)gnu.org wrote: My beam subdivision algorithm tries to strictly respect metric values as subdivision is intended to ease readers' track of the current measure position. Adding features that loosen that strictness such as one to support your desired output

Re: beam subdivision problem

2024-07-03 Thread Carl Sorensen
On Tue, Jul 2, 2024 at 10:48 AM Werner LEMBERG wrote: > > Folks, > > > how can I easily create a beam subdivision as shown in the attached > image using the current development version 2.25.18? The solution I > came up with is extremely ugly... > > > Werner > > This may be slightly less ugly

Re: beam subdivision problem

2024-07-03 Thread Werner LEMBERG
> My reading would be > > \version "2.24.3" > \relative c'' { > d4 r16 f d b g'4~ g16 a c a64 (g fis g) | > } > > It corrects only one beaming "error", is more rhythmically > consistent, and might be more in keeping with the context. Thanks, but I'm not typesetting the sonata :-) It would be

RE: beam subdivision problem

2024-07-03 Thread carsonmark
ge- From: lilypond-user-bounces+carsonmark=ca.rr@gnu.org On Behalf Of Werner LEMBERG Sent: Tuesday, July 2, 2024 9:33 PM To: sripedia_getp...@slmail.me Cc: lilypond-user@gnu.org Subject: Re: beam subdivision problem Hello Jason, > > ``` > > { > &g

Re: beam subdivision problem

2024-07-02 Thread Werner LEMBERG
Hello Jason, > > ``` > > { > > \once \set subdivideBeams = ##t > > \once \set minimumBeamSubdivisionInterval = \musicLength 8 > > f'16 f'32 > > \set stemRightBeamCount = 2 > > f' > > \set stemLeftBeamCount = 2 > >f' f' f' f' > > } > > ``` > > Looks

Re: beam subdivision problem

2024-07-02 Thread Jason Yip
Replying from my current email address since the one you cc'd me is abandoned, wish I could update the git commits' email addresses without breaking changes haha. On 2024-07-02 09:47, Werner LEMBERG 'wl at gnu.org' wrote: ``` { \once \set subdivideBeams = ##t \once \set minimumBeamSubdivisionI

Re: Beam subdivision

2015-03-10 Thread Andrew Bernard
Trevor, Thanks! Indeed lilypond is not doing the right thing, and needs to be adjustable by the user in this aspect. I can do it the original way with explicit beam control, so there is a solution. It’s just very tedious and error prone - when there are several hundred of these in the score I

Re: Beam subdivision

2015-03-10 Thread Thomas Morley
2015-03-10 22:29 GMT+01:00 Trevor Daniels : > tisimst wrote Tuesday, March 10, 2015 4:52 PM > >> The other question the OP was asking is can >> the group default to have TWO full beams >> across the group, ... >> I had a look through the IR and couldn't find >> anything that says it will only use a

Re: Beam subdivision

2015-03-10 Thread Trevor Daniels
tisimst wrote Tuesday, March 10, 2015 4:52 PM > The other question the OP was asking is can > the group default to have TWO full beams > across the group, ... > I had a look through the IR and couldn't find > anything that says it will only use a SINGLE > beam across the whole group. The sni

Re: Beam subdivision

2015-03-10 Thread Noeck
Hi, On 03/10/2015 05:52 PM, tisimst wrote: >> The other question the OP was asking is can the group default to have >> TWO full beams across the group Am 10.03.2015 um 21:01 schrieb Rutger Hofman: > So, if 32nd notes are subgrouped into groups of 4, the subgroup duration is > 1/8 and the > beam

Re: Beam subdivision

2015-03-10 Thread Rutger Hofman
On 03/10/2015 05:52 PM, tisimst wrote: The other question the OP was asking is can the group default to have TWO full beams across the group, while the pairs of 32nd notes are beamed together with a third. It seems like non-standard notation, so quick, generic solutions for any size of group, out

Re: Beam subdivision

2015-03-10 Thread tisimst
The other question the OP was asking is can the group default to have TWO full beams across the group, while the pairs of 32nd notes are beamed together with a third. It seems like non-standard notation, so quick, generic solutions for any size of group, outside of a function like the one alread

Re: Beam subdivision

2015-03-10 Thread Stephen MacNeil
\version "2.18.2" \relative c'' { % this should be all you need % if you use \once you can aply it any time \once \set subdivideBeams = ##t \set baseMoment = #(ly:make-moment 1/20) \tuplet 5/4 { % no square brackets needed e,32 c' bes e d bes' g d' d, aes' } % without \tuplet 5/4

Re: Beam subdivision

2015-03-10 Thread Kevin Barry
On Tue, Mar 10, 2015 at 12:40 PM, Andrew Bernard wrote: > This is good, and helpful, but I was wanting two beams between the groups > of 32s, not one. [Maybe this is non standard after all.] Ah my apologies; I misread your mail. A quick search didn't yield what property sets the default at one

Re: Beam subdivision

2015-03-10 Thread Andrew Bernard
This is good, and helpful, but I was wanting two beams between the groups of 32s, not one. [Maybe this is non standard after all.] On 10 March 2015 at 23:27:30, Kevin Barry (barr...@gmail.com) wrote: The following should be what you want. It works by setting the baseMoment to a theoretical val

Re: Beam subdivision

2015-03-10 Thread Kevin Barry
On Tue, Mar 10, 2015 at 12:03 PM, Andrew Bernard wrote: > How can I do this in a more idiomatic, and less tedious way than the > following? Hi Andrew, The following should be what you want. It works by setting the baseMoment to a theoretical value of 1/20 (that is, four fifths of a semiquaver,

Re: Beam subdivision bug in 2.15.22?

2011-12-17 Thread Phil Holmes
- Original Message - From: "Thomas Scharkowski" To: "lilypond-user" Sent: Friday, December 16, 2011 5:50 PM Subject: Beam subdivision bug in 2.15.22? \times 2/3 { b16 b b } b8 b4 b b 2.15.22 produces a (wrong) beam subdivison. 2.14.2 output is correct. See attachments. Is this a bu

Re: Beam subdivision bug in 2.15.22?

2011-12-16 Thread David Kastrup
Thomas Scharkowski writes: > \times 2/3 { b16 b b } b8 b4 b b > > 2.15.22 produces a (wrong) beam subdivison. > 2.14.2 output is correct. > See attachments. > > Is this a bug? > I searched the bug list but did not find this one. I would have a hard time calling this anything else. You might wan

Re: Beam subdivision and fingering in tablatures

2005-01-18 Thread Graham Percival
On 17-Jan-05, at 4:39 PM, Sebastiano Vigna wrote: sn32 sn sn \set DrumVoice.stemRightBeamCount = #1 sn \set DrumVoice.stemLeftBeamCount = #1 sn sn sn sn An example of this kind would be an excellent addition to the manual. Already exists, at least in 2.5.8. Note that the manual uses a \property mac

Re: Beam subdivision and fingering in tablatures

2005-01-17 Thread Sebastiano Vigna
On Mon, 2005-01-17 at 23:56 +0100, Erik Sandberg wrote: > You can always use stemLeftBeamCount etc. Now I got it: to get that kind of effect, you must use BOTH stemLeftBeamCount AND stemRightBeamCount on the last note of the group, as in sn32 sn sn \set DrumVoice.stemRightBeamCount = #1 sn \se

Re: Beam subdivision and fingering in tablatures

2005-01-17 Thread Erik Sandberg
On Monday 17 January 2005 22.25, Sebastiano Vigna wrote: > Two questions (I posed one in lilypond-devel, not realising it was the > wrong place): > > 1) Is there any way of forcing a beam subdivision at a certain point? I > am typesetting drum scores, and whem I have things like > > sn32[ sn sn sn