Thanks!
Thats a better solution. (But I’m still happy about having asked the wrong
question so I could learn about how to find the stencil expression)
Best
/Leo
> 3 aug. 2022 kl. 13:40 skrev Jean Abou Samra :
>
>
>
>> Le 2 août 2022 à 23:34, Leo Correia de Verdier
>> a écrit :
>>
>> Than
> Le 2 août 2022 à 23:34, Leo Correia de Verdier
> a écrit :
>
> Thanks a lot!
>
> This is impressive and is helping me a lot to both understand and manage my
> issue.
>
> Thing is I wanted narrower accidentals, and instead of doing it the proper
> way and redesigning the font I hacked th
Thanks a lot!
This is impressive and is helping me a lot to both understand and manage my
issue.
Thing is I wanted narrower accidentals, and instead of doing it the proper way
and redesigning the font I hacked them with a callback with ly:stencil-scale .
Then I realised I wanted the key signat
Yes, but support lists and forums consist of a very large percentage of
XY problems due to their very nature. :-) I always ask people 'what is
the real question?'.
Andrew
On 2/08/2022 6:50 pm, Lukas-Fabian Moser wrote:
But your question seems sounds like an xy problem
(https://en.wikipedia
Hi Leo,
Am 02.08.22 um 09:48 schrieb Leo Correia de Verdier:
Is there any way to access the stencils of individual accidentals in a key
signature?
The KeySignature stencil gets constructed by combining the individual
accidental stencils into one stencil, as can be seen here:
\version "2.23
Dear list,
Is there any way to access the stencils of individual accidentals in a key
signature?
Thanks
/Leo
