Re: Full measure rests does not display in partial measure

Am 19.11.19 um 18:34 schrieb Павел Буданов: <<    { \partial 4*3 b b b b b b b }    \\    { R1*3/4 R1 } How to solve subject problem? I did not find the answer in the archive. A partial measure is partial, not full, so why do you want a full measure rest? In 4/4 time the rest shoul

Full measure rests does not display in partial measure

<< { \partial 4*3 b b b b b b b } \\ { R1*3/4 R1 } >> How to solve subject problem? I did not find the answer in the archive.