I use jQuery $.ajax to submit user comment to a PHP Script.
The PHP script validate the user data, if it is OK, user comment is
written to mysql database. If not it will show error message.
Now the script print error message and success message same way.
I need PHP script pass one more value, t
It works fine for me, you should have made some mistake.
Just create a test page and upload to your web site with java scripts,
that is easy to see the problem.
On Jan 22, 6:09 pm, abhisek wrote:
> Thanks for your response.
> I think that was a livequery issue. Used the following function to
Can some one convert following code to jQuery ?
function check(value)
{
x = document.bulk_import.elements.length;
for(i=0;i
if possible.
>
> There is a lot of jQuery checkbox code out there, so go Googling, and
> don't expect people to just write your code for you if it's simple.
>
> On Mar 12, 10:38 am, "FlashWebHost.com" wrote:
>
> > Can some one con
Thanks all, i got it fixed now by removing @ from the beginning name=
$("input[name='article_id[]']").each(function(){
On Mar 12, 9:32 pm, "FlashWebHost.com" wrote:
> I want to check all check boxes. I made a search and made following
> page
>
> htt
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