Glad to help.
It's nothing specific to jQuery, of course. Here's a simplified test case:
var Test = function() {};
Test.prototype.foo = function() { alert('bar'); };
var test = new Test;
test.foo(); // alerts 'bar'
var Test = function() {};
var test = new Test;
tes
Don't feel bad. You made it easy for me. Since you'd already done some
investigating and ruled out a number of possibilities, all I had to do was
look at the one or two things you might have missed! :-)
On a more serious note, this thread is a great example of why we keep asking
people to post a l
Paulo, you're loading jQuery twice. First you load jQuery, then you load
your plugins, then you load jQuery again. That second load of jQuery wipes
out the original jQuery and all its plugins.
Do a View Source on your page with the sort photos link, and search for:
Could it be that you are also loading prototype.js or some other library
that redefines the $() function?
Does it find plugin methods if you use jQuery(...)... instead of $(...)...?
Do the built-in jQuery methods show up?
What does it display if you enter each of these lines into the Firebug
con
On Mon, Nov 23, 2009 at 5:55 AM, Paulodemoc wrote:
> Its the javasscript on the php page, and the only php there is to
> output the urls, and these urls are being printed correctly
> The url doesn't affect the understanding of the rest of the code...
If your plugins aren't loading, those URLs
First of all, if this is a .js script, why is there html in the first few
lines ?
Michel Belleville
2009/11/23 Paulodemoc
> Its the javasscript on the php page, and the only php there is to
> output the urls, and these urls are being printed correctly
> The url doesn't affect the understand
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