Yes, I learned a lot because of you guys! Thank you. It works like a
charm:
http://www.lightwavers.net/dadda/
cu
tom
On Jan 17, 9:37 am, Hamish Campbell <[EMAIL PROTECTED]> wrote:
> Ah so, you learn something new everyday!
>
> On Jan 16, 5:34 pm, fuzziman <[EMAIL PROTECTED]> wrote:
>
> > [EMAIL
Ah so, you learn something new everyday!
On Jan 16, 5:34 pm, fuzziman <[EMAIL PROTECTED]> wrote:
> [EMAIL PROTECTED] wrote:
>
> > Remember that variables declared within functions only exist for that
> > function.
>
> Not really...
>
> As others mentioned, the crux of the problem is because setIn
[EMAIL PROTECTED] wrote:
>
> Remember that variables declared within functions only exist for that
> function.
>
Not really...
As others mentioned, the crux of the problem is because setInterval is
calling "force()" which refers to the global scope.
Try passing in the reference to the fun
Just to elaborate (because it tripped me up when I start out too and
other js noobs like me might find it useful):
In your example, function "force" is a function within the
document.ready function:
$(document).ready(
function(){// Function called when document.ready fires
functi
The function 'force' belongs to the document.ready call, so as soon as
that's done 'force' is destroyed.
If you put it outside of the document.ready, the function exists
globally for all javascript in the page.
On Jan 16, 9:13 am, tlob <[EMAIL PROTECTED]> wrote:
> hm... why? can you explain me i
hm... why? can you explain me in detail why its not working that way?
I like to learn.
I uploaded it:
http://www.lightwavers.net/dadda/
click joda, the icons should appear and start whirling around like
this:
http://www.ontoinfo.com/2006/09/22/javascript-flying-pictures-effect/
thx
tl
On Jan 1
try with force function outside $...ready
Feijó
- Original Message -
From: "tlob" <[EMAIL PROTECTED]>
To: "jQuery (English)"
Sent: Tuesday, January 15, 2008 4:11 PM
Subject: [jQuery] simple newbie js function problem...
script type="text/javascript">
$(document).ready(function
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