[jQuery] Re: return false failing with substring

2007-07-14 Thread Michael Geary
> From: Michael Geary > > var $navleft = $("#navleft"); > $navleft.attr( "href", $navleft.attr("href").slice(0,-1) + '0' ); > > Or even this (which is probably the way I'd code it myself): > > var navleft = $("#navleft")[0]; > navleft.href = navleft.href.slice(0,-1) + '0'; I ma

[jQuery] Re: return false failing with substring

2007-07-14 Thread Michael Geary
Great, I'm glad you got it working, Steve. Check out Dan's followup comments for some good ideas on optimizing your code. I'd add one more thing to that. I suggest using the $ prefix on variable names only when you are storing a jQuery object in that variable. For example: var $this = $(th

[jQuery] Re: return false failing with substring

2007-07-14 Thread Dan G. Switzer, II
>$("#toggle").click(function(){ >$("#calendar .arc").toggle(); > $("#calendar .arc").Highlight(1000, '#ff9'); > > var $this = $(this); > if($this.is ('.show')) > { > $this.removeClass('show'); > $this.addClass('hide').empty().appe

[jQuery] Re: return false failing with substring

2007-07-14 Thread SteelSoftware
Mike, What I was trying to do was edit the last characer based upon a few conditions so that a show/hide function would work with and without javascript. As well as the errors you spotted, when i was setting the href I was setting it to #calendar .nav, and not to #calendar #navleft. The addition

[jQuery] Re: return false failing with substring

2007-07-13 Thread Michael Geary
> From: SteelSoftware > > I'm having trouble with a bit of jQuery. It seems that if I include > the following lines into my code, the page follows the link that i'm > clicking instead of staying on the same page: > > var $ref = $("#calendar .#navleft").attr("href").text(); > $("#calendar .nav").