Thank you Jules! I thought that *might* be the case, but seeing the
tell-tail jQuery code in the DHTML was a little confusing to me. But
yes, I think I understand it now. "alt" is a normal JavaScript object,
NOT jQuery. So when accessing JS objects I must always use the [0].
This also seems to app
$("#myElement) returns jQuery object and $("#myElement")[0] returns
DHTML object.
Here is a sample on how to access alt attribute
jQuery $("#myElement").attr("alt")
vs
DHTML $("#myElement")[0].alt
Both code return the same value. Correct me if i am wrong, I think
the DHTML version is faster tha
can't understand what you say.sorry.
2009/7/9 labbit
>
> Hello everyone, I tried posting a message before, but it didn't get
> posted, so here's another go.
>
> I'm completely new to jquery development and I wanted to use this date
> picker, since it also uses time as well
>
> http://razum.si/jQ
Hi bart, let me cite from the spec:
"get(): Access all matched DOM elements. This serves as a backwards-
compatible way of accessing all matched elements (other than the
jQuery object itself, which is, in fact, an array of elements). It is
useful if you need to operate on the DOM elements themsel
If the callback runs but the data isn't loaded it's almost certainly a
server error. What is in your responseText when it fails?
On Nov 4, 10:34 pm, HiddenPhoenix <[EMAIL PROTECTED]> wrote:
> im kinda a noob with some of this jquery stuff. esp the ajax stuff so
> any help i can get here would be
This forum is about using jQuery, thus I assumed that I didn't have to
spell out that I indeed of course meant the best jquery way. Thank
you for your answer.
One answer: Use the technique you mentioned, or any of the techniques the
others suggested. They will all work and are all fine to use.
Another answer: In code that is performance critical, you may want to bypass
all that and go right to the metal.
Each of your "item" elements contains a single
This forum is about using jQuery, so our answers will usually be
focused on the best JQUERY way, not necessarily the BEST way.
On Jul 2, 11:51 am, ml1 <[EMAIL PROTECTED]> wrote:
> I'm trying to find out the "best practice" for getting the contents of
> one particular element. I know about the ea
Let's say you've got the element stored in a variable as an
XMLElement, then it would be a simple matter to refer to the jQuery
object of the element itself, for example, for variable elem:
$(elem,xml).text()
On Jul 2, 12:10 pm, "Richard D. Worth" <[EMAIL PROTECTED]> wrote:
> $('item', xml).eq(1
$('item', xml).eq(1).text()
- Richard
On Wed, Jul 2, 2008 at 11:51 AM, ml1 <[EMAIL PROTECTED]> wrote:
>
> I'm trying to find out the "best practice" for getting the contents of
> one particular element. I know about the each() call.
>
> As I said I can use ways that seem not so efficient to get
I'm trying to find out the "best practice" for getting the contents of
one particular element. I know about the each() call.
As I said I can use ways that seem not so efficient to get the
contents of a single element but I want to know the best way.
On Jul 1, 5:20 pm, Mike Alsup <[EMAIL PROTECT
> I am using jquery to parse some xml. I'm looking for the best
> practice to access an elements text contents.
>
> Let's say my xml looks like this:
>
>
>
> Hello world!
>
> Goodnight moon!
>
>
>
> I can get a wrapped set of the elements this way: $('items > item',
>
Thanks a lot for the help!
Really appreciate it
-Eric
Take a look at http://brandonaaron.net/docs/livequery/
On Jun 25, 12:22 pm, Eric <[EMAIL PROTECTED]> wrote:
> I am sure this has been answered before, but I could not find it.
>
> I click on a link which loads a second page into a div using the load
> function
>
> $(document).ready(
>
What is the structure of the page you are loading into your div? Could
it be that the "new" content is causing problems, like duplicate id's,
and that is causing the inability to find elements?
On Jun 25, 10:22 am, Eric <[EMAIL PROTECTED]> wrote:
> I am sure this has been answered before, but I
For a general answer to your question, I recommend starting here:
http://docs.jquery.com/Frequently_Asked_Questions#Why_do_my_events_stop_working_after_an_Ajax_request.3F
In order to specify code to run after the ajax is complete, you can provide
a callback as the final parameter to .load(). This
Thanks, that looks like it does the job! Looks quite easy to adapt to
my requirements.
Cheers,
Adrian
On Nov 30, 6:41 pm, "Glen Lipka" <[EMAIL PROTECTED]> wrote:
> I made this a while back.http://www.commadot.com/jquery/faq.php
>
> I think it does what you want. You can change the markup to be
I made this a while back.
http://www.commadot.com/jquery/faq.php
I think it does what you want. You can change the markup to be DD/DT pretty
easily.
Glen
On Nov 30, 2007 8:47 AM, [EMAIL PROTECTED] <
[EMAIL PROTECTED]> wrote:
>
> Ladies and Gentlemen,
>
> Here goes my complete noob question:
>
Hmm...I replied to you but it didn't post my reply...just a blank
response.
Anyway, I'm using CakePHP. When a form is submitted it is validated
and all of the fields that invalidate are stored into an associative
array containing the invalid field and its corresponding error
message. Normally, th
On Nov 30, 5:55 am, Action <[EMAIL PROTECTED]> wrote:
> On Nov 29, 8:02 pm, Wizzud <[EMAIL PROTECTED]> wrote:
>
> > For example ... ?
Sorry, maybe that was a bit too cryptic.
Can you provide an example of your PHP data?
Can you provide examples of the before/after affected HTML?
Can you provide
Your best approach would be to write a PHP script that serves data in
XML or JSON format and then invoke the script from a $.ajax call in
jQuery. Then you process the data you get back and insert it into
your document as appropriate.
Sorry for being vague, but without more information that's the
There are a lot of way to take data via ajax.
I always use this one:
Client side:
data = param1=foo¶m2=bar
$.ajax({
type: "POST",
url: "ajax.php",
data: data,
dataType: "json",
success: function(data_result) { FillResult(data_result) } //
on success the Fil
hi
you can do it this way
$document({
$("div#mydiv").html("No of Users: " + "");
})
On Nov 30, 12:55 am, Action <[EMAIL PROTECTED]> wrote:
> On Nov 29, 8:02 pm, Wizzud <[EMAIL PROTECTED]> wrote:
>
>
>
> > For example ... ?
>
> > On Nov 29, 9:34 pm, Action <[EMAIL PROTECTED]> wrote:
>
> > >
On Nov 29, 8:02 pm, Wizzud <[EMAIL PROTECTED]> wrote:
> For example ... ?
>
> On Nov 29, 9:34 pm, Action <[EMAIL PROTECTED]> wrote:
>
> > I have a PHP array of data I want to be able to append to the html
> > using jquery and ajax. I want to be able to add different elements of
> > the array to
For example ... ?
On Nov 29, 9:34 pm, Action <[EMAIL PROTECTED]> wrote:
> I have a PHP array of data I want to be able to append to the html
> using jquery and ajax. I want to be able to add different elements of
> the array to different parts of the page.
>
> How can I go about doing this?
Hi John,
thanks for the info, I'll try that.
But it seems that there is another problem, because the part where
the .attr("style") thing is checked, depends on the link beiing
generated, wich does not happen in IE.
The result of the code in IE is
Text
(which is the "static" html code)
in Firefox
This is going to be an issue:
.attr("style") == "display: none;"
Up until just the other day, that wasn't working in IE (it's fixed
now, and it will be in jQuery 1.1.4). In the meantime I recommend that
you do:
.is(":hidden")
or:
.css("display") == "none"
--John
On 7/24/07, webrocker <[EMAI
Sorry, it should of course read ".append() not working in IE" in the
title of this post, not ".add() not working in IE".
:-/
Sorry, it should of course read ".append() not working in IE" in the
title of this post, not ".add() not working in IE".
:-/
Glad to have pointed you in a good direction.
On 7/24/07, tonywhite <[EMAIL PROTECTED]> wrote:
Cool - I get it now.
I found that my problem was really that the target div for inserting
my HTML wasn't set to display:none; to begin with, so animating it to
a block state was just not happening.
Cool - I get it now.
I found that my problem was really that the target div for inserting
my HTML wasn't set to display:none; to begin with, so animating it to
a block state was just not happening.
Thanks for your response - I appreciate the group.
On Jul 24, 11:08 am, "Benjamin Sterling"
<[EMA
Tony,
try:
(for an ID)
$('#emptyDiv').load(externalHTML, function(){
$(this).slideDown('slow');
});
(for a class)
$('.emptyDiv').load(externalHTML, function(){
$(this).slideDown('slow');
});
On 7/24/07, tonywhite <[EMAIL PROTECTED]> wrote:
I'm new to jQuery and can't figure this one out.
Ins
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