Here you find what bind() do:
http://docs.jquery.com/Events/bind
-Mensagem Original-
De: Saiful Haqqi
Para: jquery-en@googlegroups.com
Enviada em: quarta-feira, 7 de janeiro de 2009 20:12
Assunto: [jQuery] Re: mouseout problem
$(document).ready(
function() {
$("#text_span")
.mouseover(
function () {
$("#isPopUp
If I'm understanding correctly the hide img list function is based on
the click event, so putting the hide tooltip function inside of it
would only work if the user always clicks on every image.
On Jan 7, 1:48 pm, Kean wrote:
> In the hide img function just call hide tip.
>
> On Jan 7, 8:53 am,
In the hide img function just call hide tip.
On Jan 7, 8:53 am, "i...@wenn.com" wrote:
> We have a page that when you hover over images the tooltip shows, when
> you click on the image, the list of images is hidden but the tip seems
> to still say on the screen till i move mouse over another obj
Without an example page or code showing how the tooltips are
generated, it's very difficult to diagnose the problem.
On Jan 7, 11:53 am, "i...@wenn.com" wrote:
> We have a page that when you hover over images the tooltip shows, when
> you click on the image, the list of images is hidden but the
Hi saiful!
You have several syntax errors in your code, but I assume they're just
typos (for once, you have "isPopUp" in your one selector, instead of
"#isPopUp").
Your problem likely stems from misinterpreting the mouseout event,
though. That event fires *every time the cursor leaves a child of
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