My point was the recursion :) I know that it iterates wrong.
my last post should be :
>> pos++;
> > if( pos == $imgs.length )
> > pos = 0; // rewind
On 28 Sie, 17:52, Ariel Flesler <[EMAIL PROTECTED]> wrote:
> No, your code will hide and show back the last item.
> If I'm
No, your code will hide and show back the last item.
If I'm wrong, the code I gave you works as expected.
--
Ariel Flesler
http://flesler.blogspot.com
On Aug 28, 12:27 pm, admi99 <[EMAIL PROTECTED]> wrote:
> Thank you :) However it isn't what I need :)
> At First :
> shouldn't it be more like th
Thank you :) However it isn't what I need :)
At First :
shouldn't it be more like that :
$imgs.eq( pos ).fadeOut("slow", function(){
if( pos == $imgs.length )
pos = 0; // rewind
else pos++;
$imgs.eq( pos ).fadeIn("slow", slide );
});
Secondly,
stil there's recu
var pos= 0,
$imgs;
function slide(){
$imgs.eq( pos++ ).fadeOut("slow", function(){
if( pos == $imgs.length )
pos = 0; // rewind
$imgs.eq( pos ).fadeIn("slow", slide );
});
);
// Wait for document ready to start the magic
$(function(){
$imgs = $('img.foo');
On 03/05/2007, at 3:23 AM, [EMAIL PROTECTED] wrote:
IS there anyway to not have the slideshow:
http://interface.eyecon.ro/demos/slideshow.html
show the photo's sort of in a vertical line until they all load.
I think CSS could solve this. Maybe you could just set the ul to
position:relative a
I'll add to this if I may.
This is one of the best slideshows I have seen that have the item
highlighted in the list 1 2 3 4 etc, but after spending some time with it
was unable to get it working...more on it would be very very welcome, can
even donate :)
Bruce P
- Original Message
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