[jQuery] Re: jQuery loop help

2008-11-30 Thread SLR
First off, I want to thank everyone for such quick replies. > That will work, but it's a fairly brittle way to do things. If you add > another link earlier in your page, it will change the loop indexes and > you'll have to revise your code to match. I understand and agree with you. I don't think

[jQuery] Re: jQuery loop help

2008-11-30 Thread victorg
> > If you just want the loop index, it's passed to the .each() callback as the > > first parameter: > > >     $('a').each( function( i ){ > >         // 'i' is the loop index > >         $(this).click(function(){ > >             // You can use 'i' directly in this code > >         }); > >     })

[jQuery] Re: jQuery loop help

2008-11-30 Thread Michael Geary
> > From: Michael Geary > > But is the loop index that useful here? I'm trying to > > picture what you might do with it. There may be a > > better way to do this - if you could say more about > > your application, someone may have a suggestion. > From: SLR > To give you a brief rundown. Imagine

[jQuery] Re: jQuery loop help

2008-11-30 Thread Jeffrey Kretz
day, November 30, 2008 3:12 PM To: jQuery (English) Subject: [jQuery] Re: jQuery loop help > No question is too "noobie". Welcome aboard! :-) I appreciate the warm welcome = ) > That code won't work at all. > I would suggest reading the doc page on .each(): Definitely on my

[jQuery] Re: jQuery loop help

2008-11-30 Thread SLR
> No question is too "noobie". Welcome aboard! :-) I appreciate the warm welcome = ) > That code won't work at all. > I would suggest reading the doc page on .each(): Definitely on my to-do list... > If you just want the loop index, it's passed to the .each() callback as the > first parameter:

[jQuery] Re: jQuery loop help

2008-11-30 Thread Michael Geary
> From: SLR > > First off, I apologize if this is too "noobie" a question or > has been answered somewhere else (I can't find it anywhere). > I'm new to jQuery, and I'm trying to learn some basics. No question is too "noobie". Welcome aboard! :-) > Anyways, I'm stumped on the following. > >