[jQuery] Re: code dosen't work if put after some other code

2008-11-29 Thread Betty
Thank you, ricardo. Thank you, brian. You're such great help! Initially I used hover because it was shorter than mouseover. -.- I didn't know they had such a difference. Now it works fine. :) On Nov 29, 2:02 pm, brian <[EMAIL PROTECTED]> wrote: > As Ricardo said, hover() expects a second function

[jQuery] Re: code dosen't work if put after some other code

2008-11-28 Thread brian
As Ricardo said, hover() expects a second function. I just tested your code and it works just fine like this: $(document).ready(function() { $(".xtabber .tabcontent>div").not("#tab1").hide(); $(".xtabber .tab a").hover(function () { var xone = $(this).attr("href");

[jQuery] Re: code dosen't work if put after some other code

2008-11-28 Thread ricardobeat
hover() is meant to be passed two functions, one for mouseover and one for mouseout: http://docs.jquery.com/Events/hover However that doesn't explain why just the second one doesn't work... see if using mouseover() or bind('mouseenter',fn) helps. On Nov 29, 12:16 am, Betty <[EMAIL PROTECTED]> wr

[jQuery] Re: code dosen't work if put after some other code

2008-11-28 Thread Betty
Thank you, brian. Here is the script: $(document).ready(function() { $(".xtabber .tabcontent>div").not("#tab1").hide(); $(".xtabber .tab a").hover(function () { var xone = $(this).attr("href"); $(".xtabber .tabcontent>div").not(xone).hide();

[jQuery] Re: code dosen't work if put after some other code

2008-11-28 Thread brian
I think you'll need to post the exact code you're having problems with. On Fri, Nov 28, 2008 at 8:32 AM, Betty <[EMAIL PROTECTED]> wrote: > > Hi, I'm new. I've written two pieces of code with jQuery. Each of them > works well individually. However, if I put them one after the other, > the first o