You can loop over the colors also just by using the modulo operator
instead:
$('a').each(function(i){
i = ++i % 4;
var color =
i == 1
? 'red' : //first 4
i == 2
? 'blue' : //second group of 4
i == 3
? 'yellow' : // third group
'lime'; //fourth group and so on
$(th
Awesome Ricardo, thanks! I guess the only issue I have is that I'll
never know how many "sets of 4" I'll be dealing with, and i apologize
for not explaining myself very well in my example. Basically for each
"set", I want to run the same function. This is what I came up with.
It works, but I'm a
$('a').each(function(i){
i = Math.ceil(++i/4);
var color =
i == 1 //first 4
? 'red' :
i == 2 //other 4
? 'blue' :
i == 3
? 'yellow' : // etc
i == 4
? 'green' :
'lime';
$(this).css('backgroundColor', color);
});
On Jan 22, 11:37 pm, devilmike wrote:
> Hell
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