[jQuery] Re: XPATH question

2007-09-16 Thread Erik Beeson
Ah, right. I didn't look at it that closely. See here for more info on what Karl is referring to: http://docs.jquery.com/DOM/Traversing/Selectors#Supported_Predicates.2C_but_differently --Erik On 9/16/07, Karl Swedberg <[EMAIL PROTECTED]> wrote: > > Even with the XPath plugin, you won't be able

[jQuery] Re: XPATH question

2007-09-16 Thread Karl Swedberg
Even with the XPath plugin, you won't be able to use that selector. jQuery always only supported a subset of XPath, not the full spec. The "div[2]" part, for example, won't be recognized correctly by jQuery, in any version. --Karl _ Karl Swedberg www.englishrules.com www.le

[jQuery] Re: XPATH question

2007-09-16 Thread Erik Beeson
If you're using jQuery 1.2, you need the XPath plugin, available here: http://docs.jquery.com/Release:jQuery_1.2#XPath_Compatibility_Plugin See here for more info: http://docs.jquery.com/Release:jQuery_1.2#Removed_Functionality --Erik On 9/16/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: > >

[jQuery] Re: xpath question

2007-04-06 Thread Benjamin Sterling
Thanks Jörn. On 4/6/07, Jörn Zaefferer <[EMAIL PROTECTED]> wrote: Benjamin Sterling schrieb: > right now I am doing something like: > > $('/modules/module:eq('+currentModule+')/groups/group:eq('+currentGroup+')') > > And that is working, should I change that to something like: > > $('/modules/

[jQuery] Re: xpath question

2007-04-06 Thread Jörn Zaefferer
Benjamin Sterling schrieb: right now I am doing something like: $('/modules/module:eq('+currentModule+')/groups/group:eq('+currentGroup+')') And that is working, should I change that to something like: $('/modules/module:nth-child('+currentModule+')/groups/group:nth-child('+currentGroup+')')

[jQuery] Re: xpath question

2007-04-06 Thread Benjamin Sterling
right now I am doing something like: $('/modules/module:eq('+currentModule+')/groups/group:eq('+currentGroup+')') And that is working, should I change that to something like: $('/modules/module:nth-child('+currentModule+')/groups/group:nth-child('+currentGroup+')') What would be the difference

[jQuery] Re: xpath question

2007-04-06 Thread Jörn Zaefferer
Blair Mitchelmore schrieb: I heard John talking about adding in the "/modules/module[1]" syntax on the list a little while ago for jQuery 1.1.3 but that might have been pushed back to 1.2 Actually that is implemented in the latest revision. From what I understood, it isn't the same as :eq(n)

[jQuery] Re: xpath question

2007-04-05 Thread Benjamin Sterling
Blair, Thanks for the heads up, much appreciated. -- Benjamin Sterling http://www.KenzoMedia.com http://www.KenzoHosting.com

[jQuery] Re: xpath question

2007-04-05 Thread Blair Mitchelmore
I heard John talking about adding in the "/modules/module[1]" syntax on the list a little while ago for jQuery 1.1.3 but that might have been pushed back to 1.2 -blair [EMAIL PROTECTED] wrote: Ok, after re-reading http://docs.jquery.com/DOM/Traversing/Selectors I figured out that I should b

[jQuery] Re: xpath question

2007-04-05 Thread [EMAIL PROTECTED]
Ok, after re-reading http://docs.jquery.com/DOM/Traversing/Selectors I figured out that I should be using :eq(n) example: $('/modules/module:eq(1)', docXML[0]).attr('name') -- Benjamin Sterling http://www.KenzoMedia.com http://www.KenzoHosting.com