Thanks Erik!
On Sep 26, 1:40 pm, "Erik Beeson" <[EMAIL PROTECTED]> wrote:
> This will find all descendants: $(this).find('*');
>
> --Erik
>
> On 9/26/07, voltron <[EMAIL PROTECTED]> wrote:
>
>
>
> > I am trying to get all the children of a node, apart from adding
> > ".children()" for every gener
This will find all descendants: $(this).find('*');
--Erik
On 9/26/07, voltron <[EMAIL PROTECTED]> wrote:
>
>
> I am trying to get all the children of a node, apart from adding
> ".children()" for every generation, is there one call that gets all
> recursively?
>
> this is what I´m doing at the mo
不懂你的意思
On 9月26日, 下午3时35分, voltron <[EMAIL PROTECTED]> wrote:
> I am trying to get all the children of a node, apart from adding
> ".children()" for every generation, is there one call that gets all
> recursively?
>
> this is what I m doing at the moment
>
> $(this).children().children().removeAtt
You don't need to use children, that's for if you only want the
children...
Try this:
$('[name]', this).removeAttr("name");
http://docs.jquery.com/Selectors for more info
That'll do what you're attempting
On Sep 26, 8:35 am, voltron <[EMAIL PROTECTED]> wrote:
> I am trying to get all the chil
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