You could try doing it this way:
$('label').filter(function() {
return !$(this).parents('div.t2-display').length;
})
--Karl
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Dec 14, 2008, at 2:58 PM, Fran wrote:
I was given some very useful guidance
I was given some very useful guidance on #jquery (thanks!)
The problem is due to the fact that the 't2-display' DIV is nested
inside others.
Since the nesting is arbitrary across my application (both in terms of
levels & classes) I'll have to take the opposite approach & label up
the DIVs to which
2 matches
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