[jQuery] Re: JQuery tablesorter problem

2010-02-09 Thread Nagaraju
Hi Aquaone I am using Version 2.0.3 On Feb 4, 11:20 pm, aquaone wrote: > Please provide the code you're using to invoke tablesorter. It's likely a > syntax error. > > On Thu, Feb 4, 2010 at 05:36, Nagaraju wrote: > > I am facing problem with jquery.tablesorter.js > > > It's working fine if I ha

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread MorningZ
Sorry man, no idea what to tell you. good luck with your issue On Jan 12, 3:34 pm, "Varun Khatri" wrote: > If I remove runat="server " > Like > ** > And then use : > > $(".tablesorter") >    .tablesorter({widthFixed: true, widgets: ['zebra']}) >    .tablesorterPager({container: $("#pager")}

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread Varun Khatri
If I remove runat="server " Like ** And then use : $(".tablesorter") .tablesorter({widthFixed: true, widgets: ['zebra']}) .tablesorterPager({container: $("#pager")}) *It works fine * But If I do ** And then use : $(".tablesorter") .tablesorter({widthFixed: true, widgets: ['zebra']})

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread MorningZ
What happens with: $(".tablesorter") .tablesorter({widthFixed: true, widgets: ['zebra']}) .tablesorterPager({container: $("#pager")}) On Jan 12, 3:11 pm, "Varun Khatri" wrote: > Here I have attached 3 files ... Its just a simple example > I am trying this coz all my tables are dynam

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread MorningZ
Without seeing a working (errr, "non working") page, constantly posting the same piece of non-working code is not helping others help you How about just using a class? On Jan 12, 2:51 pm, "Varun Khatri" wrote: > well to me both returned same value So I agree > But still cant find solutio

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread Varun Khatri
well to me both returned same value So I agree But still cant find solution to problem: *alert($("#"+serverIdPrefix+"table1").size());// still returns 1* $("#"+serverIdPrefix+"table1") .tablesorter({widthFixed: true, widgets: ['zebra']}) .tablesorterPager({container: $("#pager")}) */

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread MorningZ
> Can I also use table sorter with datagrid control? No, well, not "out of the box" anyways... as the DataGrid control doesn't generate , , and tags, all of which are important parts of the TableSorter structure If you insist on using DataGrid, you'll have to make a custom control adapter that

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread MorningZ
"you shouldn't use .length on a jQuery object, since that always returns 1 afaik" size and length are equivalent, well, except that "size" is slower Straight from the docs: Length: The number of elements currently matched. The size function will return the same valu

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread Varun Khatri
*alert($("#"+serverIdPrefix+"table1").size());// still returns 1* $("#"+serverIdPrefix+"table1") .tablesorter({widthFixed: true, widgets: ['zebra']}) .tablesorterPager({container: $("#pager")}) *//still doesnot work* Is there any other mistake that you can think of that I am making here

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread Lukas Pitschl | Dressy Vagabonds
you shouldn't use .length on a jQuery object, since that always returns 1 afaik. Use .size() instead. If your alert then still reports 1 you've selected the table correctly using jQuery, else you have to check your id. also your example implies, that the serverIdPrefix is not used. Check if

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread Varun Khatri
alert($("#"+serverIdPrefix+"table1").length)); This returns 1 I dint get it Plz help Thanks Varun On Mon, Jan 12, 2009 at 4:26 AM, MorningZ wrote: > > in the "runat=server" version, put > > alert($("#"+serverIdPrefix+"table1").length)); > > right before the tablesorter line believe

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread Varun Khatri
Also, to get around the problem : I made a div around the table : // table content here I used this jquery after making div: $("#tableDiv").each(function(){ $(this).find("table").each(function() { if($(this).hasClass('tablesorter')) { $(this).tablesorter({widthFixed: true, widgets: ['zebra']

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread Varun Khatri
Can I also use table sorter with datagrid control? Thanks Varun On Mon, Jan 12, 2009 at 4:26 AM, MorningZ wrote: > > in the "runat=server" version, put > > alert($("#"+serverIdPrefix+"table1").length)); > > right before the tablesorter line believe me, as a .NET > programmer myself, the ru

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread MorningZ
in the "runat=server" version, put alert($("#"+serverIdPrefix+"table1").length)); right before the tablesorter line believe me, as a .NET programmer myself, the runat=server is *not* causing tablesorter (or jQuery) to break, you definitely are not jQuery-selecting the table properly On Ja

[jQuery] Re: Jquery tablesorter problem

2009-01-12 Thread Genus Project
when the table is generated by server side code, are you sure you are calling the correct selector ("#"+serverIdPrefix+"table1) ? maybe you missed some letter or something. you can use firebug to examine the generated table html to see if you are in fact calling the correct selector. If you are, i