Snef wrote:
>
>
> Donny Kurnia schreef:
>> Snef wrote:
>>> When using $.ajax() i encounter some problems.
>>>
>>> With the ajax I'm calling a script that will return some html. When
>>> echoing the returned data, I can see that everything is returned
>>> including the javascript tags.
>>>
>>> Wh
simple solution using your example that works
Create a js file "test.js" containing :
$('#freediv').html('test');
$("#test").click(function(){
alert("Bla");
});
I used an tag in html to click to call the test.js file as
follows:
$(document).
2009/4/15 Snef :
>
> Well a tip to all. When having problems, first give your pc a nice
> reboot ;)
Are you serious? :)
Which OS do you have?
> Suddenly it is working :S Don;t know why, but it is.
O_o
--
- -
-- Csanyi Andras -- http://sayusi.hu -- Sayusi Ando
-- "Bízzál Istenben és tar
Well a tip to all. When having problems, first give your pc a nice
reboot ;)
Suddenly it is working :S Don;t know why, but it is.
Thanx for all support!
Snef schreef:
> Donny Kurnia schreef:
> > Snef wrote:
> > > When using $.ajax() i encounter some problems.
> > >
> > > With the ajax I'm c
Donny Kurnia schreef:
> Snef wrote:
> > When using $.ajax() i encounter some problems.
> >
> > With the ajax I'm calling a script that will return some html. When
> > echoing the returned data, I can see that everything is returned
> > including the javascript tags.
> >
> > When 'inserting' the
Snef wrote:
> When using $.ajax() i encounter some problems.
>
> With the ajax I'm calling a script that will return some html. When
> echoing the returned data, I can see that everything is returned
> including the javascript tags.
>
> When 'inserting' the returned data into a div on the screen
I do not think it is due to $.ajax function. Even when using plain $
("#freediv").html(.) it won't work.
(and I don't need json yet).
András Csányi schreef:
> 2009/4/15 Snef :
> >
> > I already tried it with the $(document).ready(function(){.}). No
> > success. :(
>
> And through $.getJ
The 'problem' using .live() is that i need to have all the scripts
loaded even when they are not used. I just wanted to have only the
scripts related to that form.
The check is either in 'view generated source' in FF and the dom
inspector.
I'm not sure about eval, sounds like evil ;)
A simple al
2009/4/15 Snef :
>
> I already tried it with the $(document).ready(function(){.}). No
> success. :(
And through $.getJSON()?
At night I can send you an string what is go through json into $("#foo").html();
András
--
- -
-- Csanyi Andras -- http://sayusi.hu -- Sayusi Ando
-- "Bízzál Iste
András Csányi schreef:
> 2009/4/15 Snef :
> >
> > When using $.ajax() i encounter some problems.
> >
> > With the ajax I'm calling a script that will return some html. When
> > echoing the returned data, I can see that everything is returned
> > including the javascript tags.
> >
> > When 'inserti
2009/4/15 Snef :
>
> When using $.ajax() i encounter some problems.
>
> With the ajax I'm calling a script that will return some html. When
> echoing the returned data, I can see that everything is returned
> including the javascript tags.
>
> When 'inserting' the returned data into a div on the s
I'd suggest .live() still. Or maybe you could try eval() those
JavaScript code after Ajax fetch and DOM manipulation complete
manually? btw, do you check the page source using `view page source'
or firebug's dom inspector? latter recommended.
On Apr 15, 3:56 pm, Snef wrote:
> When using $.ajax()
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