Oh, finally I found the original thread.
I have exactly the same problem and tried everything the last 3 days
and no positive result.
So I hope somebody could help us out here.
I already validated my json response and reduced the source to a
minimum checkout where the problem could be...
--
Thanks! I'll try that.
I have an idea what it might be, but that code is at home. I think I
might not be getting rid of the prefix ColdFusion adds to json
responses -- I'll have to see if there's a preprocessing directive
like jquery's built in ajax calls have.
Scott
On Wed, Jan 6, 2010 at 9:08
What you have there should be working. Perhaps the json response is
not properly formatting. Try adding an error callback, or using the
global ajaxError hook, and see if that's the problem.
Mike
On Jan 5, 8:20 pm, Scott Brady wrote:
> I'm having an issue using the jquery form plug-in. The for
I found my very stupid mistake. I wasn't checking the type within
updateControls when I setup the submit event. Thus if I used a DIV that
contained the form two submits got fired, one for the div and one for the
form. Of course the DIV isn't really a form so it iterates the entire
document.
Tha
try changing this:
within = within ? $('#' + within) : $(document);
to this:
within = typeof(within) != 'undefined' ? $('#' + within) : $
(document);
On Sep 29, 5:33 pm, Jeremy Darling wrote:
> Sorry, guess it would help if I explained within :). The actual full method
> is:
> function updateC
Sorry, guess it would help if I explained within :). The actual full method
is:
function updateControls(within){
within = within?$('#'+within):$(document);
within.submit(validateForm);
within.find(".datepicker").datepicker();
within.find("form").submit(validateForm);
within.find(".datepi
Try changing within to $('form').
I haven't come across within so I don't know anything about it.
On Sep 29, 4:45 pm, Jeremy wrote:
> I have built out a fairly rhobust app using jquery and jquery-ui all
> was going well until we started to bring different screens together
> inside a tabbed inte
Then check the data you are sending to the server side script. There
are a few ways to do this.
In your JavaScript, you can make the data object before you call the
$.ajax() method. Then check the object in Firebug or do
alert(dataObject.FIRSTNAME) to see if it is properly formed.
You might also
I tried it as:
success: function(msg, textStatus){
alert( "Server Response: " + msg );
}
Nothing changed.
Did you try adding the textStatus parameter?
2009/8/17 efet :
>
> I tried alert, I alert box empty. But when I disable the jquery and
> submit the form as I used to, I get the error in the following format.
>
> id='message' />sorry, you cannot use this email address.
>
> On Aug 17, 2:09 pm, Milo
I tried alert, I alert box empty. But when I disable the jquery and
submit the form as I used to, I get the error in the following format.
sorry, you cannot use this email address.
On Aug 17, 2:09 pm, Miloš Rašić wrote:
> I'm quite certain that output variable in your callback function
> should
I'm quite certain that output variable in your callback function
should contain the response of your server side script. In other
words, even if your server side script displays something like a
scripting language or database error, it should still be in the output
variable. If you think something
Great explanation, thank you so much. But I still cant grab output of
page we sent the data. I still only get "Contact Form Submitted!"
message, though I know my server side codes gave an error message.
On Aug 17, 1:39 pm, Miloš Rašić wrote:
> html() method set's the innerHTML of an element, wh
html() method set's the innerHTML of an element, which means that it
overwrites what was previously in it. What you should do is:
$("#SIGNUPFORM").html(output);
$('#SIGNUPFORM').append("Contact Form Submitted!");
It would also be good for your programming for you to get a habit of
chaining method
Ok now it partially worked! I get Contact Form Submitted! message once
I click submit. But! there still is a one problem. When form
submitted, if email address is used before, my server side script
gives "sorry, you cannot use this email address" message. How can I
grab other page's response text
Your page is refreshed? No wonder since you are using type="submit"
input. Change it to type="button" and add return false; at the end of
your onclick function just in case. return false; will prevent the
button from continuing with its default behaviour once your function
is complete.
Submit inp
I missed few ""s there thank you. I am pasting the updated code here.
I just installed firebug. I dont receive any errors, what happens is
page is refreshed. Before moving to an easier method, I want to learn
this method first. I am just a beginner yet. Do you think page is
refreshed because I hav
Doesn't your browser report some errors when you try to submit the
form? Try $("[name='signup']").click when you bind the function. I've
also never seen the object notation quite like what you are using for
your data parameter. Shouldn't it be something like
$("[name='LASTNAME']").val()? If you wan
$("#itemId").val(); I found this one here http://docs.jquery.com/Attributes/val
now, when I place this inside the live() function, this should work
right? because it's already 'live' so it already has the elements from
the dynamically loaded page.
On Aug 3, 7:35 am, solow wrote:
> and for the in
and for the input text input?
On 3 aug, 07:11, waseem sabjee wrote:
> var tcC = typecoinsCASHIN.val();
> please add values to all your option tag.
>
> if(tcC == 1) {
>
>
>
> }
> On Mon, Aug 3, 2009 at 4:03 AM, solow wrote:
>
> > hello,
>
> > Recently i've discovered how to use dynamicaly loaded
var tcC = typecoinsCASHIN.val();
please add values to all your option tag.
if(tcC == 1) {
}
On Mon, Aug 3, 2009 at 4:03 AM, solow wrote:
>
> hello,
>
> Recently i've discovered how to use dynamicaly loaded content, with
> javascript.
>
> $("div ul li a").live("click", function() {
> //
donb wrote:
> The malsup link. I should say Firefox displays a 'site unavailable'
> page. Although I was directed the URL, it's apparently offline at the
> moment.
>
> On Apr 30, 12:44 pm, András Csányi wrote:
>> 2009/4/30 donb :
>>
>>
>>
>>> Whoa! That link sents me to a 'spyware-files.info'
The malsup link. I should say Firefox displays a 'site unavailable'
page. Although I was directed the URL, it's apparently offline at the
moment.
On Apr 30, 12:44 pm, András Csányi wrote:
> 2009/4/30 donb :
>
>
>
> > Whoa! That link sents me to a 'spyware-files.info' website!!!
>
> Which link
2009/4/30 donb :
>
> Whoa! That link sents me to a 'spyware-files.info' website!!!
Which link? What I'm suggested or my blogs link? Both working for me.
--
- -
-- Csanyi Andras -- http://sayusi.hu -- Sayusi Ando
-- "Bízzál Istenben és tartsd szárazon a puskaport!".-- Cromwell
Whoa! That link sents me to a 'spyware-files.info' website!!!
On Apr 30, 12:30 pm, András Csányi wrote:
> 2009/4/30 Ben :
>
>
>
> > I am having trouble submitting a form by clicking on a button " > type='submit' />" while I am waiting for the callback of the $.getJSON
> > function to fire.
>
>
2009/4/30 Ben :
>
> I am having trouble submitting a form by clicking on a button " type='submit' />" while I am waiting for the callback of the $.getJSON
> function to fire.
>
> Is there a way to allow the form to submit even if the callback is
> never called?
Have you tried this?
http://malsup.
heh. you could also set the submit input to disabled. something like
this:
var $mySubmit = $('form :submit');
$mySubmit.attr('disabled', true);
$('form :input').one('change', function() {
$mySubmit.attr('disabled', false);
});
--Karl
Karl Swedberg
www.englishrules.com
www.learn
$('form').bind('submit.disable', function() {
return false;
}).find(':input').one('change', function() {
$(this).closest('form').unbind('submit.disable');
});
This should get you started. You might want to add/remove a class,
too, to indicate the form's state.
Note that I namespaced the ev
Thank you Guys.
I got it to work now with following Code, maybe it helps somebody out
there with a similar NyroModal Problem:
Does not work( Removes the Modal but still does not fire the Submit() )
("#form-config-content-make").submit(function()
{
top.$.nyroModalRemove();
return true;
})
> $(".form-config-content-make-button").click(function() {
> $("#form-config-content-make").submit(top.$.nyroModalRemove());
>
> });
That's not a "callback" function, it's a "call me right now" function
because you've included the paretheses.
It may be better to observe form's submit event instead of the buttons. This
fires the event no matter how the form was submitted (for example, press
"enter" when an input field is focused).
("#form-config-content-make").submit(function()
{
top.$.nyroModalRemove();
return true; // submits t
I thing confusing you,
I tel what i want ?
I want to submit form without page refresh,
Is there any best link other then wha u given last,
One more thing am having some script,
But am expecting help is, i want to implement into drupal,,,
2008/11/10 Sam Sherlock <[EMAIL PROTECTED]>
> I thi
you could change the example to work with another data type
if you don't have json php ext - its included in php 5.2+ (something like
that)
so either
1. upgrade php - or use a php class for json
2. make the json as a basic print "{'myName': $myName}"
3. use another data type xml for exa
working example with json
2 files first index.html
http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd";>
http://www.w3.org/1999/xhtml"; xml:lang="en-US"
lang="en-US">
malsup jquery form to php
http://www.malsup.com/jquery/jquery-1.2.6.js";>
http://www.malsup.c
How to approach other for this problem,(With Drupal)
2008/11/10 bharani kumar <[EMAIL PROTECTED]>
> I Got
>
> : *Fatal error*: Call to undefined function json_encode() in *C:\Program
> Files\xampp\htdocs\source\ajaxformsubmit\sample2\test.php* on line *7*
>
>
> One more thing the form is redirect
u got it, what i am expecting
2008/11/10 bharani kumar <[EMAIL PROTECTED]>
> Hi here is my module, i want to add the JQuery into this module,
> ,
> that is form submit without page refresh ,
>
> 2008/11/10 bharani kumar <[EMAIL PROTECTED]>
>
>> I thing confusing you,
>>
>> I tel what i want ?
>>
Hi here is my module, i want to add the JQuery into this module,
that is form submit without page refresh ,
2008/11/10 bharani kumar <[EMAIL PROTECTED]>
> I thing confusing you,
>
> I tel what i want ?
>
> I want to submit form without page refresh,
>
> Is there any best link other then wha u gi
>
>
thats jquery - you'll need that for jquery to work. also you'll need to be
accessing the form plugin
see my previous message :)
2008/11/10 bharani kumar <[EMAIL PROTECTED]>
> what is use
> of this script,
>
> I removed this script,
>
> Output same, no changes,
>
> Thanks
>
>
> 2008/1
I think we are misunderstand each other a bit
I asked to see you html - I saw the example and the form is not submitted by
ajax
I was asking if your form has an id of myForm eg
would also be helpful if you could post link to example does not store ip's
after submitting
2008/11/10 bharani kum
what is use
of this script,
I removed this script,
Output same, no changes,
Thanks
2008/11/10 bharani kumar <[EMAIL PROTECTED]>
> Hi u see , in that page is loading / redirecting know,
> But my thing is without page reloading to submit the form,
>
>
> Got my point , one more thing , am havi
Hi u see , in that page is loading / redirecting know,
But my thing is without page reloading to submit the form,
Got my point , one more thing , am having some jquery script , which working
fine (without page refresh to form submiting)
But i need the help in, i want to use the jquery in Drupa
Hi u see , in that page is loading / redirecting know,
But my thing is without page reloading to submit the form,
Got my point , one more thing , am having some jquery script , which working
fine (without page refresh to form submiting)
But i need the help in, i want to use the jquery in Drupa
whats the html - I saw the link and that form did not appear to have the
event applied to the form
perhaps this could be solved by checking that the id of the form is myForm.
I know nothing of drupal
I can check back to the link since its logged my ip and now tells me I have
already voted visit t
Hi...
What happen?
Any Greate drupal please try to spend a min..thanks
On Mon, Nov 10, 2008 at 6:22 PM, bharani kumar <
[EMAIL PROTECTED]> wrote:
> But , i want to implement in Drupal ,
>
> Am not sure the below code correct,
>
> In this i want to add the JQuery,
>
>
> function custom3_block(
But , i want to implement in Drupal ,
Am not sure the below code correct,
In this i want to add the JQuery,
// wait for the DOM to be loaded
$(document).ready(function() { alert("Tets")
$("#myForm").ajaxForm(function() {
alert("Thank you for your comm
this should be your solution
http://www.malsup.com/jquery/form/
2008/11/10 [EMAIL PROTECTED] <[EMAIL PROTECTED]>
>
> Hi Friends
>
> I just want to submit the form without page refresh i want to do this
> using j query,
>
>
> Am actually working in DRUPAL ,Tell me how to implement this in
> drupa
Thanks alot, can't believe i haven't tried changing that form item ...
feels stupig but happy it's resolved :)
Chris
On 5 jul, 01:40, Mike Alsup <[EMAIL PROTECTED]> wrote:
> > What is wrong with this code?
>
> > $(document).ready(function() {
> > $("#f_submit").hide();
> > $("#f
> What is wrong with this code?
>
> $(document).ready(function() {
> $("#f_submit").hide();
> $("#f_altsubmit").click(function(event) {
> $("#checkoutform")[0].submit();
> return false;
> });
>
> });
>
> In FF3 this throws an error in the Err
On Nov 6, 2:41 pm, "Samuel Vogel" <[EMAIL PROTECTED]> wrote:
> Hey guys,
>
> It seems that I'm unable to make up the right search term for google to find
> what I'm looking for:
> The eays jQuery way to make my form get submitted as soon as the user
> chooses an element from my select box.
>
> Sho
This should do it:
$("#myselectid").change(function() {
document.formname.submit();
});
-- Josh
- Original Message -
From: Samuel Vogel
To: jquery-en@googlegroups.com
Sent: Tuesday, November 06, 2007 2:41 PM
Subject: [jQuery] form submit on choosing select option
He
I've replaced
options = jQuery.extend(options);
with
options = options || {};
and it works now.
Thanx Mike !
On Jul 5, 5:00 pm, "Mike Alsup" <[EMAIL PROTECTED]> wrote:
> Most likely the problem occurs because you're using the extend method
> incorrectly. If you only pass a single arg to ext
Most likely the problem occurs because you're using the extend method
incorrectly. If you only pass a single arg to extend it extends the
jQuery object. I'm not really sure what you're trying to accomplish
with this line anyway:
options = jQuery.extend(options);
Did you mean to use something
John,
I'm developing a framework here and everything went well `till I
started asking myself. Does it work if I have 2 forms present on one
page?
And all came tumbling down since, the submit event takes the second
set of options everytime i click the form submit button.
Shouldn't the first optio
Carlin,
It seems like a wrong approach to submit more than one form. By virtue a
form is sort of a "domain" of information. If you have seperate forms they
likely should be submitted seperately. There are ways to combine information
so the form is split up into pages or even "tabs" for example of
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