[jQuery] Re: Fadein with ajax load()

try: $('#id-of-my-div').load('somescript.php?name='+escape($(this).val()), {}).fadeIn("slow"); On Jul 2, 9:35 am, Pickledegg <[EMAIL PROTECTED]> wrote: > Thanks Equand, unfortunately my fadeIn doesn't seem to have any > effect. Hmm, maybe its because the contents of the div has already > been lo

[jQuery] Re: Fadein with ajax load()

Thanks Equand, unfortunately my fadeIn doesn't seem to have any effect. Hmm, maybe its because the contents of the div has already been loaded at this point? Perhaps I'll have to go a bit more technical than just using the load method... On Jul 1, 11:56 pm, Equand <[EMAIL PROTECTED]> wrote: > tr

[jQuery] Re: Fadein with ajax load()

try $('#id-of-my-div').load('somescript.php?name='+escape($(this).val()), {},function(){ $('#id-of-my-div').fadeIn("slow") }); http://docs.jquery.com/Ajax/load#urldatacallback On 1 июл, 14:26, Pickledegg <[EMAIL PROTECTED]> wrote: > I'm using an ajax load() with an onChange event: > > $('#id-of-