excellent - thanks Mike!
malsup wrote:
>
>
> You could do something like this:
>
> $('div.containerClass').each(function() {
> var p = this.parentNode;
> $(this).cycle({
> fx: 'scrollHorz',
> speed: 'slow',
> timeout: 0,
> next: $('a.next', p),
You could do something like this:
$('div.containerClass').each(function() {
var p = this.parentNode;
$(this).cycle({
fx: 'scrollHorz',
speed: 'slow',
timeout: 0,
next: $('a.next', p),
prev: $('a.prev', p)
});
});
Mike
On 9/6/07, rol
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