Thanks a lot for the help James. I'll give that a shot. I am re-
tooling this little application and I'm beginning to think I may not
need tables at all. I'll keep you posted.
Thanks again
On Jul 13, 8:24 pm, James wrote:
> I think there's some issues with fadeIn/fadeOut for .
> Try something
I think there's some issues with fadeIn/fadeOut for .
Try something like the following:
var html = 'hello';
$('#groups').append(html).find("td").fadeIn("fast");
The class "hide" on the is style with display:none;
Add this to all your if you have more than one.
On Jul 13, 2:05 pm, Nate wrote:
LOL - I swear I thought of almost the exact same thing when I went out
and took a drive...it's amazing what time away from the computer
does...and of course, a little help.
Now I seem to be missing something (yeah, I am new to jQuery...)
I still want that table row to fade in...but neither metho
How about just removing the empty and use something like the
following for your insert row after your AJAX response:
$("#groups").append('');
On Jul 13, 1:00 pm, Nate wrote:
> Also, James, each table row has a unique id. it will be called
> something like id="group34" or id="group35" - no
Also, James, each table row has a unique id. it will be called
something like id="group34" or id="group35" - no two are the same.
It's info that is related to the ID of the database.
So when my jQuery posts to addgroup.php, it inserts the data into the
database, and then I use the mysql_inser_id
Here is the PHP code that generates the entire table, plus the empty table
row.
I don't see anywhere in the code where you're setting an ID to the
. And if you're cloning an existing that has an ID, that may
cause issues because IDs are suppose to be unique on a page.
Is there any reason you're cloning an existing instead of
just appending it in with all the other content?
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