with 1.3.1 I'm able to get pixel measurement from percent with no
problem.
example:
test
alert($("#d1").width());
alert($("#d2").width());
alert($("#d3").width());
alert($("#d4").width());
On Jan 28, 12:17 pm, Kevin Da
Thanks Matt, but that does not work.
As my example shows, the element may have a percentage width, or it
could be 'auto' (which it would be if not specifically set). What I
need is the 'pixel' measurement that would replicate its current size.
In other words, if it currently is width:90%; and I r
$('#Test').css('width') ?
On Jan 26, 11:46 am, Kevin Dalman wrote:
> jQuery has innerHeight/Width and outerHeight/Width methods, but is
> there a method that can return a 'CSS Height/Width'. A CSS width is
> the width that would be applied via CSS to achieve a given 'outer
> width'. This value w
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