yeah, if you are not using cross domain calls, dump the callback
parameter there, it's totally no needed... and if you are not using
cross domain, then you aren't/don't-need-to use or think about "jsonp"
at all
as for mime type of normal json:
application/json
or
text/plain also works for fine (i
On Mon, Oct 26, 2009 at 9:58 PM, MorningZ wrote:
>
> if this is your *exact* code
>
> $.getJSON(url + "?callback?", function (json) {
>
> then you're missing an equal sign
>
> $.getJSON(url + "?callback=?", function (json) {
Good catch! Fortunately I had the = in my real code. I just forgot to
t
if this is your *exact* code
$.getJSON(url + "?callback?", function (json) {
then you're missing an equal sign
$.getJSON(url + "?callback=?", function (json) {
As for the rest of your issue of "what to do", this post should help:
http://groups.google.com/group/jquery-en/browse_thread/thread/f
Actually I am sending data to the server from a form so post is needed. But
I do agree that normally get is teh better method if you don't need to send
data to a server.
Joey
On Wed, Aug 12, 2009 at 2:27 PM, Michael Geary wrote:
>
> > > From: Michael Geary
> > > Just use $.getJSON() or $.ajax()
> > From: Michael Geary
> > Just use $.getJSON() or $.ajax() with the 'json' or 'jsonp'
> > dataType as needed.
> From: Stephan Beal
> Speaking of: i recommend AGAINST using getJSON() because it
> muddles up my Apache logs horribly (the JSON gets encoded in
> the request, which gets logged as
m] On
Behalf Of Joey Derrico
Sent: Tuesday, August 11, 2009 12:17 PM
To: jquery-en@googlegroups.com
Subject: [jQuery] Re: AJAX and JSON
Ok so I have used .ajax function to run my ajax and set type to data. It is
getting (well posting) to a php file that echo's a json_encoded array. When
it r
Ok so I have used .ajax function to run my ajax and set type to data. It is
getting (well posting) to a php file that echo's a json_encoded array. When
it returns I am using console.log to display the returned data. when I just
use data it shows the JSON encoded data, but if I use data.key I get
un
On Aug 11, 6:14 am, Cam Spiers wrote:
> I also recommend using json2.js for anything more then just a basic
> key-value json string.
Another nice feature of json2.js is that you can use it to deeply
clone objects:
var orig = {};
var clone = JSON.parse(JSON.stringify(orig));
i've found tha
On Aug 11, 5:13 am, MorningZ wrote:
> I'd also recommend against use of $.getJSON for a totally different
> reason:
>
> There is no option to "catch" errors.
You can: you have to set a global ajax error handler to catch it,
though. Not pretty, but it's suitable for many simple cases (where a
I also recommend using json2.js for anything more then just a basic
key-value json string.
I ran into troubles with the standard jQuery json approach, when
implementing a complex system that transfers a lot of json to and from the
server.
And as Michael Geary mentions:
"If you want to *generate*
"Speaking of: i recommend AGAINST using getJSON()"
I'd also recommend against use of $.getJSON for a totally different
reason:
There is no option to "catch" errors.
getJSON: function(url, data, callback) {
return jQuery.get(url, data, callback, "json");
},
so if something happens serv
I'll just add my 2 cents from novice to novice.
1. JSON is just a lightweight markup language. Its like HTML, and more
like XML but just without the weight. And it is easier to read with
the eyeball.
JSON uses {} squiggles and : and [] and others to markup the data.
JSON {"CATALOG" : "JCPENNY"}
X
On Aug 11, 12:26 am, "Michael Geary" wrote:
> Just use $.getJSON() or $.ajax() with the 'json' or 'jsonp' dataType as
> needed.
Speaking of: i recommend AGAINST using getJSON() because it muddles up
my Apache logs horribly (the JSON gets encoded in the request, which
gets logged as urlencoded ga
> > From: Joey Derrico
> >
> > I am a novice at AJAX and JSON (Ok, I am a novice at
> > JavaScript.), and
> > I am brand new to jQuery. I wanted to use JSON in a project I am
> > working on and I read various tutorials on using JSON with jQuery
> > however none of them answered some of my ques
On Aug 10, 9:58 pm, Joey Derrico wrote:
> I am a novice at AJAX and JSON (Ok, I am a novice at JavaScript.), and I am
> brand new to jQuery. I wanted to use JSON in a project I am working on and I
> read various tutorials on using JSON with jQuery however none of them
> answered some of my questi
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