Hmm. I am creating hidden form elements and i am inserting returned result
to that element. Here is sample cod:
function ajaxFileUpload()
{
$.ajaxFileUpload
(
{
url:base_modal+'c=content&m=uploadFile',
secureuri:false,
hi Yılmaz
thanks for the reply..
I followed your (good) advice with some change. This is what i did:
1- deleted the url:' option from ajaxFileUpload function, so my php
file is called rightly once;
2- when i call the jquery $.ajax function i clone the input created
from the $.ajaxFileUpload int
I am using this plugin just like that.
... my other form elements
Choose File :
... other elements, my form is huge :)
ajaxFileUpload() does not need to be posting your form. It's already
creating iframe and posting file over this element. So, you can use like
this, i am using with
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