Typo indeed ^^°
Though the principle is sound.
Michel Belleville
2009/11/8 Sam Doyle
> $(this).fadeOu(duration, function() {
>
>
> Typo
>
> Sent from my iPhone
>
> On 8 Nov 2009, at 07:27, Michel Belleville
> wrote:
>
> $(this).fadeOu(duration, function() {
>
>
$(this).fadeOu(duration, function() {
Typo
Sent from my iPhone
On 8 Nov 2009, at 07:27, Michel Belleville
wrote:
$(this).fadeOu(duration, function() {
When you start an animation like fadeIn() the animation starts in the
background and the script goes on without waiting the animation ton
complete, so with your each you're changing the texts one by one blazingly
fast even before the first fadeIn() completes.
What you might want instead is somethi
Hi, real simple problem, but I am struggling to find a solution. I
have an array:
var arr = [ "one", "two", "three", "four", "five" ];
and I want to fade the values in and out, moving on to the next one.
I've tried 'jQuery.each()', for loops, and so on, but I either get the
last one of t
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