0 pm, Jörn Zaefferer
wrote:
> Try this:
>
> var form = $("#myform").
> form.validate();
> $("#mybutton").click(function() {
> if (form.valid()) {
> // do something
> }
>
> });
>
> Jörn
>
> On Mon, Mar 16, 2009 at 12:0
I'm using this fantastic validation module:
http://bassistance.de/jquery-plugins/jquery-plugin-validation/ and I
wonder if there is a way to force validation before form submission.
I have a button, which my users have to click first, and if the
validation goes through then I will use window:prin
Just an update:
Today I updated to 1.3.1, update validation,form, and livequery
plugins to the newest as well.
Now the validation works find, which is totally great. However, I
still have problem with this error:
jQuery.queue is not a function
There are many ways to re-produce this error, for ex
an not find
duplicated id or something like that. I must be doing something wrong,
maybe I used some type of bad coding which is tolerated by 1.2.6 but
not so in 1.3.0 *_*
Raine
On Jan 19, 9:50 pm, yellow1912 wrote:
> Yup, exactly. If you login first, and then go back to the page, you
> wil
this.
Raine
On Jan 19, 9:42 pm, Ricardo Tomasi wrote:
> Checkout page gives me a "validator is undefined" error... I could
> register a new user, but couldn't go past the "shipping method" page
> (which also gave me the same error).
>
> On Jan 19, 7:59
eed to provide a demo online else we can't figure out the
> problem.
>
> --
> Ariel Fleslerhttp://flesler.blogspot.com
>
> On Jan 19, 4:23 pm,yellow1912 wrote:
>
> > Oops, Im sorry but
> > $(selector + ' .step[title='+currentIndex+'] div.stepCont
1.3 has some problem with selectors as far as I can tell, I would
refrain upgrading until those problems are solved, hopefully in 1.3.1
Regards
On Jan 19, 1:47 pm, beysk wrote:
> Now that you point that out it seems so obvious - since nothing was
> happening I assumed it wasn't actually working
Oops, Im sorry but
$(selector + ' .step[title='+currentIndex+'] div.stepContent').fadeOut
("slow");
-->jQuery.queue is not a function
On Jan 19, 12:22 pm, yellow1912 wrote:
> I think I found out something closer to the root cause:
>
> $(selector + &#
I think I found out something closer to the root cause:
$(selector + ' .step[title='+currentIndex+'] .stepContent').fadeOut
("slow");
-->jQuery.queue is not a function
$(selector + ' .step[title='+currentIndex+'].stepContent').fadeOut
("slow");
--> no error, but obviously not producing the effec
Hi John,
Unfortunately I have it on my localhost now, will try to upload asap.
However, I found out a bunch of errors, probably because of my bad
jquery *_*
First: in the plugin I have these line of codes, working fine in 1.2.6
but in 1.3 they prevent some even binding (see point Second)
When I try to use jquery 1.3 on my test site, I get this error:
jQuery.queue is not a function
[Break on this error] var queue = jQuery.queue( this, type, data );
(firebug)
The site is using livequery, form, metadata and validate plugin in,
all upgraded for 1.3 support.
Weird.
I still desperately need help for this, since I dont have Mac to test
and debug it. If you can help please let me know, I will pay for your
time or donate the amount to jquery, whichever method you wants.
Thanks so much for your help
Regards
Raine
On Jan 13, 6:01 pm, yellow1912 wrote:
>
I encounter a rather weird problem where my plugin would run on all
platforms except Firefox 3 on MacOSX, and since I don't have Mac I can
not debug it.
(this plugin uses jquery 1.2.6 and jq form, jq validation and
livequery plugins.)
This is still under development I can not post the link direct
Update: append() the script to head or any where on the page does give
the desired effect. I dont know why it did not work when I tried
before.
I hope this helps someone else.
And Thanks Mike and Josh, you really helped me out
Best regards
Raine
On Jan 9, 4:15 pm, yellow1912 wrote:
> I
irebug:
>
> Eval("<script>alert('hello');"); FAIL
>
> Eval("alert('hello')"); SUCCEED
>
> -- Josh
>
> -Original Message-
> From: jquery-en@googlegroups.com [mailto:jquery...@googlegroups.com] On
>
> Behalf Of yellow1912
I actually did, I put a very simple line
alert("testing");
No error, no effect, weird.
Regards
Raine
On Jan 9, 3:35 pm, MorningZ wrote:
> "I wonder if eval will work correctly in this case? "
>
> Did you simply just try it?
>
> On Jan 9, 4:01 pm, y
Thanks Mike,
These inline script always come with
When I use firebug to check the json data returned, it looks like
this:
(I just post part of the code here)
"jscript_inline":"
After I submit my form via ajax, I sometimes get back content (json
format) with some inline jscript in one of the fields (i.e:
result.jscript)
I've been trying to do something like this:
$('#output').append(result.jscript);
It doesn't seem to work, however.
(In my case, I can't avoid these inl
Inside the plugin I try this:
$this = this;
$this.livequery(function() {
$this.ajaxForm(options);
});
On Jan 6, 10:08 am, Ricardo Tomasi wrote:
> Not sure that this is it, but
>
> $.fn.myplugin = function(options) {
> return this.find('form').ajaxForm(
Hi all, I have a question regarding jquery object:
if I bind my plugin like this:
$('#myButton').myplugin();
And inside my plugin, I want to bind ajaxForm listener to all forms
inside 'this' current element, what is the best way to do it? I can
get the id by using $this.attr('id'), but there i
First I have to admit I haven't got a clear understand of js object,
array and associative array yet.
I'm using jquery form to post a form, and I get back some data in json
form, which is an array containing several fields (status, content,
etc)
The 'content' is an associative array which ca
Hi Mike,
I can't thank you enough for taking your time to teach this newbie how
to do it right. I really appreciate your help
Sincerely
Raine
On Jan 2, 12:40 pm, "Michael Geary" wrote:
> Don't thank me, Joe, thank Brendan Eich who developed JavaScript. :-)
>
> (But thanks for your comment the
Thanks Mike,
I'm following this tutorial here:
http://www.learningjquery.com/2007/10/a-plugin-development-pattern
I have several public functions like this:
$.fn.response.redirect.default = function (){//something here};
$.fn.response.redirect.type1 = function (){//something here};
$.fn.respons
Something like this
var func = 'myFunc';
Can I call the function like this for example:
$.fn.myplugin.(func)();
(I'm using this in a plugin I'm working on)
Thank you very much
ping out the domain,
> making the path relative to the current page, etc.
>
> What is it that you want to do with the path once you read it with
> javascript?
>
> JK
>
> -Original Message-
> From: jquery-en@googlegroups.com [mailto:[EMAIL PROTECTED] On
>
> Behal
I have encountered a really annoying problem with ie6 and 7:
When I append an img like this
The src is automatically changed to the http:// form
It doesnt happen on FF though. Anyone knows why this happens?
Regards
I wonder if jquery supports something like this? (like php isset()
function)
I know I can certainly write a function for it, but I dont want to re-
invent the wheel if jquery already supports it
Regards
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