it:
>
> > setTimeout(function() {
> > tabdiv.children('#tabs').tabs("select","#tabs-2");
>
> > }, 0);
>
> > Lead me to changing the order of opening the dialog and selecting the
> > other tab:
>
> > content.dialog(&
Hi all,
I've found a bug in jQuery 1.3.2 (or maybe Dialog/Tabs in UI 1.6rc6).
In my application, I have a dialog with tabs inside of it. I create
the dialog and build/setup the elements inside it before it is
displayed to the user. Up to jQuery 1.3.1 I haven't had a problem
with this. Dependi
of value. Sorry. Yeah, that looks like an error in the
> docs. Returns the jQuery object, as nearly all jQuery methods do (except in
> cases like .data(name) where they're a getter and can't return a jQuery
> object to continue the chain).
>
> - Richard
>
> On Tue,
t; <[EMAIL PROTECTED]> wrote:
> Do you have some sample code showing the problem?
>
> - Richard
>
> On Tue, Dec 9, 2008 at 5:12 PM, mgl <[EMAIL PROTECTED]> wrote:
>
> > The docs athttp://docs.jquery.com/Coresay that jQuery.data
> > (name,value) should return the value, but instead it seems to be
> > returning jQuery. Is this what is supposed to happen?
;
> The $('div').data('test') will return you the value.
>
> George
>
> On Dec 9, 5:12 pm, mgl <[EMAIL PROTECTED]> wrote:
>
> > The docs athttp://docs.jquery.com/Coresaythat jQuery.data
> > (name,value) should return the value, but instead it seems to be
> > returning jQuery. Is this what is supposed to happen?
The docs at http://docs.jquery.com/Core say that jQuery.data
(name,value) should return the value, but instead it seems to be
returning jQuery. Is this what is supposed to happen?
Cool, thanks.
On Dec 9, 8:13 pm, ricardobeat <[EMAIL PROTECTED]> wrote:
> The simplest alternative is to write a filter function:
>
> $("element").filter(function(){
> return $(this).attr('attribute') <= x;
>
> });
>
> - ricardo
>
> O
ain both classes
> $('div').find('.class-one.class-two');
>
> -Hector
>
> On Mon, Dec 8, 2008 at 7:28 PM, mgl <[EMAIL PROTECTED]> wrote:
>
> > Hello again,
>
> > Does anyone know how (or if it is possible) to select eleme
Hello again,
Does anyone know how (or if it is possible) to select elements by
multiple class names?
For example, given the following div elements:
If I wanted to get all div elements that have *both* class-one and
class-two, the only straight-forward way I can think of is the
following:
$(
Hello everyone,
I'm wondering if there is a way to select element with an attribute
filter that uses greater-than, or less-than operators. Something like
this:
$("element[attribute<=value]");
I don't see anything equivalent in the documentation...if this doesn't
exist, are there any simple alt
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