Exactly, thanks James. For some reason I found tutorial code that had $
("inp...@name=product_id]").click(); instead of $("input
[name=product_id]").click(); and so this broke it... I was close.
THANK YOU
On Sep 30, 1:28 pm, James wrote:
> With your HTML, you can do it two simple ways:
>
> By cl
Thanks for the reply Robert. :) Because the "product_id" represents
grouping of radio boxes, I wanted a single click event on the
product_id, then handle the display of the hidden checkboxes
accordingly.
As I thought, I had the name selector wrong.
Instead of using this:
$("product_id").click()
27;).is(':checked');
>
> As you can see, that's almost the same as your previous attempt; the only
> thing missing was the "return".
>
> -Mike
>
> On Tue, Sep 22, 2009 at 12:58 PM, kevin.mccormick
> wrote:
>
>
>
> > Wow I fi
Wow I finally got it... updated code here:
referrerother: {
required: function(element){
if
($('#chkStatus5').is(':checked')){
return true;
I'm getting close to finding a way to give a boolean result if the
"other" checkbox is selected (id chkStatus5)... still not working
though
referrerother: {
required: function(element){
$('#referrer-chkStatu
Im trying to implement this and Im not sure if there is a syntax
difference in returning a value of a checkbox vs a dropdown menu. Is
(return $("#referrer").val() == 'Other') the proper way to test the
value of a checkbox? It certainly works for dropdown menus..
Here is my new code, mimicking the
oohh that is just plain wonderful. thank you very much :)
On Sep 22, 9:56 am, Loony2nz wrote:
> Check out this example:
>
> http://www.coldfusionjedi.com/index.cfm/2009/2/16/jQuery-Form-Validat...
>
> On Sep 22, 9:35 am, ripcurlksm wrote:
>
> > I have a "How did you hear about us?" with a serie
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