No. $thisCell is initialized with a null value in the current scope.
- pw
On May 13, 11:12 pm, runrunforest wrote:
> Hi,
>
> I see this line in a plugin
>
> var $thisCell, $tgt = $(event.target);
>
> does that mean:
>
> var $thisCell = $(event.target);
> var $tgt = $(event.target);
[ ] is an array literal, like { } is an object literal.
var obj = json[0];
You shouldn't use eval on JSON. If you specify 'json' as your return
type, jQuery will safely eval valid JSON.
- pw
On May 12, 9:05 pm, sneaks wrote:
> hi, in firebug my callback data(object) is like so:
>
> [{"produc
$.get('/endpoint/', '', function (html) {
$(html).find('.selector').appendTo('.target');
}), 'html');
On May 11, 3:23 pm, "cstolwor...@gmail.com"
wrote:
> I have an ajax call that will be returning a large chunk of HTML. The
> thing is that this HTML needs to go to several different places on
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