I have selected a list that contains sub-lists. Now, I'd like to
search for the list items that contain sub-lists (but not including
the sub-list-items). I think the example below will explain what I'm
trying to do.
HTML:
Do Not Need
NEED THIS ITEM
Do Not Need
Do Not Need
I know this is a easy fix, I'm doing something wrong...
I've selected multiple tables and tried to use each for applying
cornering to each table. Inside the callback function, I try to find
the first/last table cells to apply cornering for each corner.
However, when there are multiple tables it l
This is a double post, at least going to be a double post from in the
jQuery Plugin list. I'm being moderated yet on that list, and it
doesn't seem to get much activity.
--
Hi, I'm going to post this here since the Tablesort
For some reason I cannot get jQuery.css('name') to return a style
property that was assigned by a class. However, it returns the
property if it was assigned by style="". Has anyone else run into this
issue? Bug? Here is my test code:
http://www.w3.org/
TR/html4/strict.dtd">
CSS Test
.apply-bo
for that, while the error should
happen immediately when the user is offline.
Any idea's are welcome.
Thanks!
PanMan.
On Apr 20, 4:02 pm, "Mauricio \(Maujor\) Samy Silva"
wrote:
> >A timeout is not considered an error.
>
> No. It's an error.
>
> Do the follo
---
> Are you sure that your request spends more than 10s ?
>
> Maurício
Hi!
I tried this while offline. The jquery JsonP lib times-out directly
(which would be my preference). But I'm sure nothing loads in 10s,
since I'm offline. (this is for an app over flaky mobile connections).
PanMan.
},
"success": function(data){
var json = $.xml2json(data);
gotdata(json, target);
}
});
This works, but the error is never thrown. If I change the URL to
something that's broken, I do get the error message, but on timeout it
never happens.
Am I doing anything wrong? Or is this a bug somewhere?
Thanks!
PanMan.
Sounds simple but I cannot get it to work. Here is the structure.
Abc
Abc
Abc
Abc
123
Abc
Abc
I want to get the last in the _sub_ list. Here is what I've tried
with no success. Ideas?
$('.list li li:last a').addClass('last-li');
$('.list li ul li:last a
to a
> single .js file that you load with a single tag.
>
> Maybe explain more about why you want a bootstrap file, and what exactly you
> want it to do?
>
> -Mike
>
> > From: Panman
>
> > Are browsers able to cache calls from jQuery.getScript
> > (http:// do
Are browsers able to cache calls from jQuery.getScript (http://
docs.jquery.com/Ajax/jQuery.getScript)? I'm just trying to determine
either to use that or just use HTML tags to get jQuery plugin
files and such. Would like the most officiant option. The reason
being, I'd like to break out the firs
I cannot for the life of me figure this out. I know it must be easy,
just not finding the solution.
I'd like to toggle() something and use the "slide" effect. However, I
don't like how the UI slide effect works. It slides the content out of
view then brings whatever was below up. I'd rather have
Andrea, when I changed to hover() the stopPropagation() effected
negatively. Once I removed that it started working ok. Also, what is
variable e when passing it to the function? Thanks
On May 9, 11:25 am, andrea varnier <[EMAIL PROTECTED]> wrote:
> not sure but you could try something like this,
Getting closer! I changed from using the mouseover() and mouseout() to
hover(). That now seems to be working properly. The only issue at this
point is that it doesn't slide down on the first hover. When the page
loads and the mouse is over the it just shows the list as the CSS
does. Then when the
e the menu working with CSS I just wanted
to add the slide down/up feature.
On May 8, 7:29 pm, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]>
wrote:
> Hello, Panman! Welcome.
>
> It would help if you posted a link to your work page.
>
> Without seeing your actual code, it looks
Hi, new to jQuery and very impressed. I already have a CSS menu that
shows/hides a list menu. However, I'd like to add more "dynamics" and
have the sub menus slide down and back up. So using the below code,
I've got it to slide down and up, but repeatedly. It seems like it
wants to keep sliding fo
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