I was looking for .keyup() not .change(), sorry.
Please ignore.
On Dec 16, 3:37 pm, Brett Alton wrote:
>
>
> src="<a rel="nofollow" href="http://ajax.googleapis.com/ajax/">http://ajax.googleapis.com/ajax/</a>
>
I'm trying to get jQuery to asynchronously load my recaptcha module,
but it doesn't seem to like the fact that "echo recaptcha_get_html
($publickey);" spits out a mixture of HMTL and Javascript.
Here's the code I am trying:
$.ajax({
url: "inc/captcha.php",
is explicitly pressed it's value won't be sent.
> So in the case given, since there are no other form elements, nothing
> with be posted to the server.
>
> Karl Rudd
>
> On Wed, Dec 24, 2008 at 11:36 PM, Brett Alton
> wrote:
>
> > How do I get PHP to pri
How do I get PHP to print JavaScript variables via $_POST? jQuery's
$.post doesn't seem to be submitting any data.
This is a sample of what I have...
test.php:
--
';
print_r($_POST);
echo '
--
jquery.js:
--
$(document).ready(functio
t).ready(function()
> {
> $("a").each(function(i){
> $(this).click(function(){
> alert(i);
>
> });
> });
> });
>
> Brian.
>
> On Wed, Dec 10, 2008 at 10:29 AM, Brett Alton <[EMAIL PROTECTED]>wrote:
>
>
>
> > Sorry, I'm new to Google Gro
Sorry, I'm new to Google Groups and was trying to reply to a post but
couldn't figure out how without e-mailing the author directly[1].
I'm trying to add the click() event to the each() loop constructor.
e.g.
$(document).ready(function()
{
$("a[id*='activate-']").each(function(i){
I'm trying to take the input from one text input field to the next and
I'm not sure how to do it through jQuery. Can someone please send me a
tutorial or example of how to do so?
Right now I have:
$(document).ready(function()
{
$("#agentfirstname").change(function()
{
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