delegate("click", ":radio, :checkbox", delegate);
to:
$(this.currentForm)
.delegate("focusin focusout keyup", ":text, :password, :file,
textarea", delegate)
.delegate("focusin focusout keyup change", "select", delegate)
.delegate(&
I've tried several ways, but I can't seem to force the jQuery
Validator to (re)validate the dropdown during the onchange.
Current scenario of a required dropdown:
1) Do not select an option and submit form.
2) Let validator validate the form.
3) Validator will show errors and higlight invalid fie
g this anyway?
Cheers, B
On May 29, 11:13 pm, BalusC wrote:
> The server side (JSP/Servlet in this case) can throw an unexpected
> exception (ServletException in this case). The exception is on the
> server side handled as an error page, which returns just a complete
> HTML page with t
The server side (JSP/Servlet in this case) can throw an unexpected
exception (ServletException in this case). The exception is on the
server side handled as an error page, which returns just a complete
HTML page with the exception details. I'd like to let ajaxSubmit's
error option show the entire
').slideDown(500);
$('#step2form').slideUp(500);
}
return false;
});
[/code]
On Apr 17, 1:23 pm, BalusC wrote:
> I thought I already have added the [validate] tag to the subject?
> Anyway, now it's done again.
>
> On Apr 17, 12:31 pm,
I thought I already have added the [validate] tag to the subject?
Anyway, now it's done again.
On Apr 17, 12:31 pm, BalusC wrote:
> I've a paged form with back and next buttons on each form.
> Each button invokes an ajaxSubmit() using submitHandler.
> Next button should disp
I've a paged form with back and next buttons on each form.
Each button invokes an ajaxSubmit() using submitHandler.
Next button should display next form using slideUp() and slideDown().
Back button should display previous form using slideUp() and slideDown
().
Here's an example of 2nd form (step)
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