t = $("#link_"+id);
next.addClass('current');
current.fadeOut('slow', function(){
next.fadeIn('slow');
});
return false;
});
-
problem is that next element appears while current element is still
fading out, any idea what i'm doing wrong?
Aljosa Mohorovic
thanks, i had an extra comma. i had no problem with decimal value,
replacing comma with dot was not a problem but what would you do if
you need to output decimal number with comma instead dot?
i'm asking because croatia (country in europe) has decimal comma, not
dot.
Aljosa
i have a problem with $.getJSON(), nothing is logged in firebug
console although i can see that correct data is returned in response
(in firebug) for code:
>>>
$.getJSON(url, function(data){
console.log(data);
});
<<<
same code, but using $.get instead $.getJSON works as expected:
>>>
$.get(u
i have:
$("a.delete").click(function() { alert("test") });
after i fetch some json data and append new html:
// on json load
$("div.items).append("test");
click events on items inserted after json data is loaded are not
working, how can i tell jquery to inspect DOM again and attach actions
on ne
if i have test
$("a.test").click(function() {
arg1 = $(this).attr('arg1');
arg2 = $(this).attr('arg2');
// code using args
});
is this acceptable way of using attr or should i avoid this?
i'm using jquery for most of javascript related things and i finally
decided that i should do it better 8-)
my plan is to improve my knowledge so i'm looking for some advanced
books and i found:
Learning jQuery: Better Interaction Design and Web Development with
Simple JavaScript Techniques by Ka
i have a select box with name "brands" and i can access currently
selected option using
$('[EMAIL PROTECTED]').val()
will val() always return currently selected option?
Aljosa Mohorovic
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