hi, thx.
I think i forget the ^0.5
cheers
Jason
On 2/6/06, Yonik Seeley <[EMAIL PROTECTED]> wrote:
>
> Hi Jason,
> I get the same thing for the queryNorm when I calculate it by hand:
> 1/((1.7613963**2 + 1.326625**2)**.5) = 0.45349488111693986
>
> -Yonik
>
> On 2/6/06, jason <[EMAIL PROTECTED]
Hi Jason,
I get the same thing for the queryNorm when I calculate it by hand:
1/((1.7613963**2 + 1.326625**2)**.5) = 0.45349488111693986
-Yonik
On 2/6/06, jason <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I have a problem of understanding the queryNorm and fieldNorm.
>
> The following is an example. I
Hi,
I have a problem of understanding the queryNorm and fieldNorm.
The following is an example. I try to follow what said in the Javadoc
"Computes the normalization value for a query given the sum of the squared
weights of each of the query terms". But the result is different.
ID:0 C:/PDF2Text/S
