5.2 32bit situation at the moment
(int)(PHP_INT_MAX +1) < (int)(PHP_INT_MAX +100) < (int)(PHP_INT_MAX + 1000)
This does seem pretty sensible. I'm more worried about the 64bit case where:
(int)(PHP_INT_MAX +1) == (int)(PHP_INT_MAX +100) < (int)(PHP_INT_MAX + 1000)
It would be nice for the 64 bi
On windows x86_64, PHP_INT_MAX is 2147483647. This is because in the
underlying c-code, a long is 32 bit.
However, linux on x86_64 uses a 64bit long so PHP_INT_MAX is going to be
9223372036854775807.
Kenan R Sulayman wrote:
Hi Lain!
As much as I did understand, this might be a pretty good i
Hi Lain!
As much as I did understand, this might be a pretty good idea.
Anyhow, you want to make this variable to be constant?
I think, this might break some calculations.-
And another question:
Does anyone knows, why PHP is showing 2147483647 as PHP_INT_MAX ? *truly,
I'm running x64*
Thanks,
-
Hi Iain,
(Yes, this subject has me sending a message to the list again instead of
lurking, and I should be back with some internals stuff again soon, hehe.
:^))
- Original Message -
From: "Iain Lewis"
Sent: Wednesday, February 04, 2009
Subject: [PHP-DEV] casting doubles to ints
> Hello a
